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[英]How do I check if a string contains ALL letters of the alphabet in python?
[英]Python : how to count amount of letters of alphabet in string in parts
如何计算不同部分之间此字符串中的字母数量? 还有另一种方法:给定数字时如何获得字母字符串表示形式?
输入:“ AG HO P Q-Z”
输出:(7,8,1,10)
q = list()
for i in seq:
if i is char:
n = ord(i+1) - ord(i)
q.append(n)
你可以这样做:
input_string = 'A-G H-O P Q-Z'
input_string = input_string.split()
q = []
for dletter in input_string:
if '-' in dletter:
q.append(1 + ord(dletter[2]) - ord(dletter[0]))
else:
q.append(1)
或者,不带if
语句:
input_string = 'A-G H-O P Q-Z'
input_string = input_string.split()
q = []
for dletter in input_string:
q.append(1 + ord(dletter[-1]) - ord(dletter[0]))
但这是一个很好的答案
a = "A-G N B-Z"
a = a.split()
b = []
for i in a:
b.extend([i.split("-")])
print(b)
for lists in b:
if len(lists) > 1:
print(lists, ":", ord(lists[1]) - ord(lists[0]) + 1)
else:
print(lists, ":", 1)
输出量
[['A', 'G'], ['N'], ['B', 'Z']]
['A', 'G'] : 7
['N'] : 1
['B', 'Z'] : 25
a = "A-G N B-Z"
b = [i.split("-") for i in a.split()]
print(b)
for lists in b:
if len(lists) > 1:
print(lists, ":", ord(lists[1]) - ord(lists[0]) + 1)
else:
print(lists, ":", 1)
输出量
[['A', 'G'], ['N'], ['B', 'Z']]
['A', 'G'] : 7
['N'] : 1
['B', 'Z'] : 25
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