Python : how to count amount of letters of alphabet in string in parts

Question

How to count the amount of letters in this string between the different parts? And the other way around: how to get the alphabetical string representation when the numbers are given?

Input: 'AG HO P Q-Z'

Output: (7, 8, 1, 10)

  q = list()

    for i in seq:
        if i is char:
            n = ord(i+1) - ord(i)
            q.append(n)

Answer 1

You can do this:

input_string = 'A-G H-O P Q-Z'
input_string = input_string.split()

q = []
for dletter in input_string:
    if '-' in dletter:
        q.append(1 + ord(dletter[2]) - ord(dletter[0]))
    else:
        q.append(1)

Alternatively without the if statement:

input_string = 'A-G H-O P Q-Z'
input_string = input_string.split()

q = []
for dletter in input_string:
    q.append(1 + ord(dletter[-1]) - ord(dletter[0]))

But this is a very good answer

Answer 2

a = "A-G  N B-Z"
a = a.split()
b = []
for i in a:
    b.extend([i.split("-")])
print(b)
for lists in b:
    if len(lists) > 1:
        print(lists, ":", ord(lists[1]) - ord(lists[0]) + 1)
    else:
        print(lists, ":", 1)

Output

[['A', 'G'], ['N'], ['B', 'Z']]
['A', 'G'] : 7
['N'] : 1
['B', 'Z'] : 25

Using list comprehension

a = "A-G  N B-Z"

b = [i.split("-") for i in a.split()]

print(b)
for lists in b:
    if len(lists) > 1:
        print(lists, ":", ord(lists[1]) - ord(lists[0]) + 1)
    else:
        print(lists, ":", 1)

Output

[['A', 'G'], ['N'], ['B', 'Z']]
['A', 'G'] : 7
['N'] : 1
['B', 'Z'] : 25