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[英]How do I structure a while-loop to not include an empty-string or quit entry in a print statement?
[英]How do i quit and print the events in one loop here
import pygame
pygame.init()
x = height,width = (800,600)
Display = pygame.display.set_mode(x)
pygame.display.set_caption("Blocky")
red = (157, 139, 215)
black = (0,0,0)
Display.fill(red)
pygame.draw.rect(Display,black,(120,450,600,50))
#It updates every frame
pygame.display.update()
excape = False
while not excape:
for dork in pygame.event.get():
print(dork)
if pygame.event == pygame.QUIT:
pygame.quit()
quit()
这里的print(dork)工作正常,但是当我单击窗口的退出按钮时,它根本不会退出。那么,我如何同时在1 while循环中同时打印事件和退出应用程序呢?
首先,您应该在while not exape循环中更新屏幕。 其次,设置excape至True
,如果pygame.event等于pygame.QUIT
。 因此,您的代码将如下所示:
import pygame, sys
pygame.init()
x = height,width = (800,600)
Display = pygame.display.set_mode(x)
pygame.display.set_caption("Blocky")
red = (157, 139, 215)
black = (0,0,0)
Display.fill(red)
pygame.draw.rect(Display,black,(120,450,600,50))
#It updates every frame
excape = False
while not excape:
for event in pygame.event.get():
print(event)
if event.type == pygame.QUIT:
excape = True
pygame.quit()
sys.exit()
pygame.display.update()
您需要循环浏览每个pygame事件,并检查该事件是否已退出。
while not excape:
for event in pygame.event.get():
print(event)
if event.type == pygame.QUIT:
pygame.quit()
excape = True
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