[英]How to print out the first input/value of a variable? C++
所以我正在编写一个程序,用于打印从1开始的连续正整数和,而事实是我想以某种形式表示最终和,以打印出我在输入开始时输入的“ n”程序,但在完成所有计算后将打印出“ n”。
#include <iostream>
using namespace std;
int main()
{
int sum,n;
cout << "Enter a number to be added consecutively starting from 1: ";
cin >> n;
do
{
sum = sum + n;
n--;
}
while(n > 0);
cout<<"The consecutive sum starting from 1 to "<< n <<"="<< sum <<endl;
return 0;
}
所以我的意思是,在最后一个cout中,它将“ n”打印为1,因为那是“ n”停止再次进入do-while循环的时候。 我想打印出开头输入的'n'作为输入/
感谢大家的所有帮助和答复! 阅读您的回复后,我想改善它
#include <iostream>
int main()
{
int sum,n;
sum = 0;
std::cout<<"\nEnter a number to be added consecutively starting from 1:";
std::cin>>n;
int t=n;
for (n ; n>0 ; n--)
{
sum = sum + n;
}
std::cout<<"\nThe consecutive sum starting from 1 to "<<t<<" = "<<sum;
return 0;
}
谢谢!
将n的值存储到其他变量中,并使用该变量显示该值! 或这样做
#include <iostream>
using namespace std;
int main()
{
int sum,n;
cout << "Enter a number to be added consecutively starting from 1: ";
cin >> n;
cout<<"The consecutive sum starting from 1 to "<< n ;
do
{
sum = sum + n;
n--;
}
while(n > 0);
cout<<"="<< sum <<endl;
return 0;
}
这将提供所需的输出!
您可以将其存储在另一个变量中,并在最后打印出来:
#include <iostream>
using namespace std;
int main()
{
int sum = 0, n;
cout << "Enter a number to be added consecutively starting from 1: ";
cin >> n;
int t = n;
do
{
sum = sum + n;
n--;
} while (n > 0);
cout << "The consecutive sum starting from 1 to " << t << "=" << sum << endl;
return 0;
}
另外,定义和时,sum不会自动设置为0(初始化)。
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