Python Split Output在方括号中

Question

我有看起来像这样的代码：

import re
activity = "Basketball - Girls 9th"
activity = re.sub(r'\s', ' ', activity).split('-')
activity = str(activity [1:2]) + str(activity [0:1])
print("".join(activity))

我希望输出看起来像Girl's 9th Basketball ，但打印时的当前输出是[' Girls 9th']['Basketball ']我想摆脱方括号。 我知道我可以简单地修剪它，但是我宁愿知道如何正确地修剪它。

Answer 1

您正在用清单print(someList) ，这与使用print(someList) -它是将[] print(someList)起来的清单的表示形式。

import re
activity = "Basketball - Girls 9th"
activity = re.sub(r'\s', ' ', activity).split('-')
activity =  activity [1:2]  + [" "] +  activity [0:1] # reorders and reassignes list

print("".join(activity))

您可以考虑添加一个步骤：

# remove empty list items and remove trailing/leading strings
cleaned = [x.strip() for x in activity if x.strip() != ""]

print(" ".join(cleaned)) # put a space between each list item

这只是对列表进行排序，并在它们之间添加所需的空格，因此您可以输出拟合。

Answer 2

你快到了。 在list上使用.join ，它将创建一个string因此您可以省略该步骤。

import re
activity = "Basketball - Girls 9th"
activity = re.sub(r'\s', ' ', activity).split('-')
activity = activity[1:2] + activity[0:1]
print(" ".join(activity))

Answer 3

您可以在一行中解决它：

new_activity = ' '.join(activity.split(' - ')[::-1])

Answer 4

您可以尝试如下操作：

import re
activity = "Basketball - Girls 9th"
activity = re.sub(r'\s', ' ', activity).split('-')
activity = str(activity [1:2][0]).strip() + ' ' + str(activity [0:1][0])
print(activity)

输出：

Girls 9th Basketball