[英]How to add trailing zeros to csv file
我努力了
num_columns = 982
def transform_row(row):
#row = row.split('\n') # split on new line
row = row.split(',') # split on commas
row = [i.split() for i in row if i!='5'] # remove 5s
row += ['0']*(num_columns - len(row)) # add 0s to end
return ','.join(row)
#and then apply this over the csv.
out = open('outfile.csv', 'w')
for row in open('dataset_TR1.csv'):
out.write(transform_row(row))
本质上,我想从csv文件的每一行中删除所有5,并用在982和983列之间的尾随0代替丢失的长度。但是,使用http://www.filedropper.com/datasettr1中的数据文件,似乎只将所有内容都写到一行,并且输出不符合预期。
您必须分别处理逗号和换行符,以使其正确。
rows = "1,5,5,5,3\n2,5,5,5,9"
rows = rows.split('\n')
lines = []
for idx, row in enumerate(rows):
row = row.split(',') # split on commas
row = [i for i in row if i!='5'] # remove 5s
row += ['0']*(5 - len(row)) # add 0s to end
row = ','.join(row)
lines.append(row)
print(rows)
lines = '\n'.join(lines)
print(lines)
扫描并在\\ n上分割。 然后逐一扫描每行,进行替换,然后放回所有内容。
更好的方法是使用内置模块csv
import csv
num_columns = 982
def transform_row(row):
row = [column for column in row if column != '5']
row += ['0'] * (num_columns - len(row))
return row
fout = open('outfile.csv', 'w', newline='')
writer = csv.writer(fout)
fin = open('dataset_TR1.csv', 'r')
reader = csv.reader(fin)
for row in reader:
writer.writerow(transform_row(row))
import csv
with open('dataset_TR1.csv', 'r') as f:
reader = csv.reader(f)
result = []
for line in reader:
print(len(line))
remove_5s = [elem for elem in line if elem != '5']
trailing_zeros = ['0'] * (len(line) - len(remove_5s))
# if you want the zeros added to the end of the line
# result.append(remove_5s + trailing_zeros)
# or if you want the zeros added before the last element of the line
result.append(remove_5s[:-1] + trailing_zeros + [remove_5s[-1]])
with open('output.csv', 'w') as f:
writer = csv.writer(f)
writer.writerows(result)
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