替换字典或嵌套字典或字典列表中键值的泛型函数

Question

所以我有一个像这样的词典：

{
  "environment": [
    {
      "appliances": [
        {
          "services-status": "GOOD",
          "ping-status": "REACHABLE"
        },
        {
          "softwareVersion": "16.1-R1-S2 50b46b5 20170829",
          "services-status": "GOOD",
          "ping-status": "REACHABLE"
        }
      ],
      "vd_url": "https://bla1"
    },
    {
      "appliances": [
        {
          "ipAddress": "10.4.64.108"
          "type": "branch",
          "sync-status": "IN_SYNC"
        },
        {
          "services-status": "GOOD",
          "ping-status": "REACHABLE"
          "sync-status": "IN_SYNC"
        }
      ],
      "vd_url": "https://bla2"
    },
  ],
  "failed_urls": [
    "https://gslburl",
    "https://gslburl",
    "https://localhost",
    "https://localhost",
    "https://localhost"
  ]
}

或可能是这样的

{
  "softwareVersion": "16.1-R1-S2 50b46b5 20170829",
  "services-status": "GOOD",
  "ping-status": "REACHABLE"
  "vd_url" : "https://blah3"
}

或可能是这样的

{
  "environment": [
    {
      "appliances": [
        {
          "services-status": "GOOD",
          "ping-status": "REACHABLE"
        },
        {
          "softwareVersion": "16.1-R1-S2 50b46b5 20170829",
          "services-status": "GOOD",
          "ping-status": "REACHABLE"
        }
      ],
      "vd_url": "https://bla1"
    }
  ]
}

或者它可以是字典的任意组合，但是我试图实现的是编写一个通用函数，该函数可以接收字典，用另一个值替换键并返回新字典。 只是一个伪代码：

def replace(dict_obj, key, new_value)
    for dict in dict_obj:
        for k, v in dict.items()
        if k == key:
              dict[k] = new_value

    return dict_obj

但是最后我想要一个与我传递的字典相同的字典对象-dict_obj，但是具有新的值，它应该适用于上面的任何类型的字典。

Answer 1

您可以使用递归来确定键，值对中的值是列表还是字典，然后进行相应的迭代。

def replace(dict_obj, key, new_value):
    for k,v in dict_obj.iteritems():
        if isinstance(v,dict):
            # replace key in dict
            replace(v, key, new_value)
        if isinstance(v,list):
            # iterate through list
            for item in v:
                if isinstance(item,dict):
                    replace(item, key, new_value)
        if k == key:
            dict_obj[k] = new_value