[英]PySide2 with qml as ui
我正在使用pyqt5和pyside2来处理qtquick2控件,即使pySide2声称它们是pyQt语法和逻辑,但并非总是如此,而且pySide2文档要么严重过时,要么根本不准确。 (我确实意识到pySide2还没有准备好正确使用,但是我仍然会尝试摆脱它)
例如插槽使用我确实得到pyQt5
@pyqtSlot()
def sayHi(self):
print("Hi")
pySide2
@Slot()
def sayHi(self):
print("Hi")
然后仅从myQml调用该函数即可。
但是我需要替代品:
@pyqtProperty(float, notify=currentValueChanged)
@currentValue.setter
variableX =pyqtSignal()
最后一个实际的代码:
import sys
import os
from PyQt5.QtCore import QObject, QUrl, Qt, pyqtSlot, pyqtSignal, pyqtProperty
from PyQt5.QtWidgets import QApplication
from PyQt5.QtQml import QQmlApplicationEngine
class Manager(QObject):
#slider Value
currentValueChanged = pyqtSignal()
def __init__(self):
QObject.__init__(self)
self.m_currentValue =0
#slider
self.currentValueChanged.connect(self.on_currentValueChanged)
#slide stuff
@pyqtProperty(float, notify=currentValueChanged)
def currentValue(self):
return self.m_currentValue
#slider
@currentValue.setter
def currentValue(self, val):
if self.m_currentValue == val:
return
self.m_currentValue = val
self.currentValueChanged.emit()
#slider VOlUME CHANGED <<<<<<<<<<<<<<<<<<<<<<<<< WORKS>>>>>>>>>>>>>>>>>>>>>>
@pyqtSlot()
def on_currentValueChanged(self):
print(self.m_currentValue)
if __name__ == "__main__":
os.environ["QT_QUICK_CONTROLS_STYLE"] = "Material"
app = QApplication(sys.argv)
engine = QQmlApplicationEngine()
manager = Manager()
ctx = engine.rootContext()
ctx.setContextProperty("Manager", manager)
engine.load('main.qml')
if not engine.rootObjects():
sys.exit(-1)
sys.exit(app.exec_())
QML
import QtQuick 2.10
import QtQuick.Controls 2.1
import QtQuick.Window 2.2
import QtQuick.Controls.Material 2.3
ApplicationWindow {
id: applicationWindow
Material.theme: Material.Light
title: qsTr("Test Invoke")
visible: true
width: 600
height: 500
Slider {
id: slider
x: 160
y: 311
value: 0.5
property bool updateValueWhileDragging: true
onMoved: Manager.currentValue = value
}
}
例如,上面的代码使用pyQT5和qtQuick2在滑块移动时仅打印出滑块的值。
有没有办法用pySide2来实现这一点,我尝试了一些选项,并且我可以在pySide中进行简单的按钮单击,但是,对于pySide中的属性和设置器,我没有发现任何有价值的信息。 (好吧,我发现的东西已经过时了,而且对于qtQuick1也是如此)
如果有人给我一个可行的例子,或指出我某个地方,我将非常感激! 干杯
对于PySide2
它具有相同的PySide
命名法,因此我建议您检查以下链接 。
对于PySide,您必须使用类似于pyqtProperty的Property,Slot等于pyqtSlot,Signal等于pyqtSignal。
import sys
import os
from PySide2.QtCore import Qt, QObject, Signal, Slot, Property
from PySide2.QtGui import QGuiApplication
from PySide2.QtQml import QQmlApplicationEngine
class Manager(QObject):
currentValueChanged = Signal()
def __init__(self):
QObject.__init__(self)
self.m_currentValue = 0.0
self.currentValueChanged.connect(self.on_currentValueChanged)
@Property(float, notify=currentValueChanged)
def currentValue(self):
return self.m_currentValue
@currentValue.setter
def setCurrentValue(self, val):
if self.m_currentValue == val:
return
self.m_currentValue = val
self.currentValueChanged.emit()
@Slot()
def on_currentValueChanged(self):
print(self.m_currentValue)
if __name__ == "__main__":
os.environ["QT_QUICK_CONTROLS_STYLE"] = "Material"
app = QGuiApplication(sys.argv)
engine = QQmlApplicationEngine()
manager = Manager()
ctx = engine.rootContext()
ctx.setContextProperty("Manager", manager)
engine.load('main.qml')
if not engine.rootObjects():
sys.exit(-1)
sys.exit(app.exec_())
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