[英]Registering a type in QML using PySide2
我正在尝试使用 Python 创建新的 QML 类型,但在注册 QML 类型时遇到问题。 但是,我收到一个错误:
TypeError: 'PySide2.QtQml.qmlRegisterType' called with wrong argument types:
PySide2.QtQml.qmlRegisterType(module, str, int, int, str)
Supported signatures:
PySide2.QtQml.qmlRegisterType(type, str, int, int, str)
所以我知道它期待一种类型,但是,在这篇博文中它做了类似的事情:
qmlRegisterType(PieChart, 'Charts', 1, 0, 'PieChart')
在我的 main.py 中,我有这个:
...
if __name__ == '__main__':
# Declare QApplication
app=QApplication([])
qmlRegisterType(CamFeed, 'CFeed', 1, 0, 'CamFeed')
...
CamFeed.py 看起来像这样:
from PySide2.QtQuick import QQuickPaintedItem
from PySide2.QtGui import QPainter
from PySide2.QtCore import QObject
class CamFeed(QQuickPaintedItem):
def __init__(self, parent=None):
super().__init__(parent)
# Re-implementation of the virtual function
def paint(self, painter):
painter.drawRect(10,10,50,50)
当然,在 main.py 文件中,您正在通过以下方式导入 CamFeed.py:
import CamFeed
if __name__ == '__main__':
# Declare QApplication
app = QApplication([])
qmlRegisterType(CamFeed, 'CFeed', 1, 0, 'CamFeed')
在这种情况下,CamFeed 是模块(.py 文件),因此有两种解决方案:
1.
from CamFeed import CamFeed
if __name__ == '__main__':
# Declare QApplication
app = QApplication([])
qmlRegisterType(CamFeed, 'CFeed', 1, 0, 'CamFeed')
2.
import CamFeed
if __name__ == '__main__':
# Declare QApplication
app = QApplication([])
qmlRegisterType(CamFeed.CamFeed, 'CFeed', 1, 0, 'CamFeed')
另一方面,按照约定小写的名称:
camfeed.py
from PySide2.QtQuick import QQuickPaintedItem
from PySide2.QtGui import QPainter
from PySide2.QtCore import QObject
class CamFeed(QQuickPaintedItem):
def __init__(self, parent=None):
super().__init__(parent)
# Re-implementation of the virtual function
def paint(self, painter):
painter.drawRect(10,10,50,50)
主文件
from camfeed import CamFeed
if __name__ == '__main__':
# Declare QApplication
app = QApplication([])
qmlRegisterType(CamFeed, 'CFeed', 1, 0, 'CamFeed')
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