Python嵌套字典和列表将具有列表值的字典键合并

Question

我有一个嵌套的字典，如下所示：

list = { "A" : [ "1", "2", "3" ], "B" :  [ "2" ], "C" : [ "1", "2" ] }

我想串联字典键和列表值，如下所示：

[ "A.1", "A.2", "A.3", "B.2", "C.1", "C.2" ]

有什么建议么？

Answer 1

您可以尝试以下代码：

list = { "A" : [ "1", "2", "3" ], "B" :  [ "2" ], "C" : [ "1", "2" ] }
data = []
for key, values in list.items():
    for value in values:
        data.append("{0}.{1}".format(key,value))
print(data)
# Output ['A.1', 'A.2', 'A.3', 'B.2', 'C.1', 'C.2']

Answer 2

lst = {"A": ["1", "2", "3"], "B": ["2"], "C": ["1", "2"]}
result = ["{}.{}".format(key, val)
          for key, vals in lst.items()
          for val in vals]
print(result)

Answer 3

new_list = []
for ks, vs in list.items():
    for v in vs:
        new_list.append('.'.join([ks, v]))

print(new_list)
# output
['A.1', 'A.2', 'A.3', 'C.1', 'C.2', 'B.2']

Answer 4

用字典的对值循环，然后将每个单独的值附加到空列表中。