[英]How to get the line number on which exception or error occurred in Python?
我有一个像这样的Django ORM查询:
try:
specialization_object = Specialization.objects.get(name="My Test Specialization")
except Exception as ex:
print(ex)
当发生异常时,它会打印“不存在专业匹配查询。”,但不会打印行号。 如何跟踪发生异常或错误的行号?
尝试这个:
import logging
logger = logging.getLogger(__name__)
try:
specialization_object = Specialization.objects.get(name="My Test Specialization")
except Exception as ex:
logger.info(ex, exc_info=True) # exc_info will add traceback
进一步阅读请看这里
如果您由于某种原因无法使用日志记录,则有标准的包traceback ,您可以执行以下操作:
traceback.print_exc(file=sys.stdout)
我刚刚想出一个简单的解决方案:
import traceback
try:
specialization_object = Specialization.objects.get(name="My Test Specialization")
except Exception as ex:
print(traceback.format_exc())
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