R：如何将x汇总并分成多列？ 乐趣=独特

Question

我正在按edu（教育级别）和id_study聚合一个data.frame，而我正在使用的功能是“唯一的”。

db1 <- aggregate (edu ~ id_study, data=steps, FUN=unique)

我得到的结果是正确的，但是（用于edu的）字符串被转换为数字元素，并且都在一列中。 我该如何纠正？ 正确答案的人会打勾！

谢谢大家阅读本文并提供帮助。

编辑****************以下是数据集。

小号

structure(c("DZA_2003_STEPS", "DZA_2003_STEPS", "DZA_2003_STEPS", 
"DZA_2003_STEPS", "DZA_2003_STEPS", "DZA_2003_STEPS", "DZA_2003_STEPS", 
"DZA_2003_STEPS", "DZA_2003_STEPS", "DZA_2003_STEPS", "DZA_2003_STEPS", 
"DZA_2003_STEPS", "DZA_2003_STEPS", "DZA_2003_STEPS", "DZA_2003_STEPS", 
"DZA_2003_STEPS", "DZA_2003_STEPS", "DZA_2003_STEPS", "DZA_2003_STEPS", 
"DZA_2003_STEPS", "9", "7", "6", "9", "7", "6", "3", "12", "3", 
"3", "3", "3", "3", "6", "6", "3", "3", "6", "11", "7"), .Dim = c(20L, 
2L))

      [,id_study]      [edu]
 [1,] "DZA_2003_STEPS" "9" 
 [2,] "DZA_2003_STEPS" "7" 
 [3,] "DZA_2003_STEPS" "6" 
 [4,] "DZA_2003_STEPS" "9" 
 [5,] "DZA_2003_STEPS" "7" 
 [6,] "DZA_2003_STEPS" "6" 
 [7,] "DZA_2003_STEPS" "3" 
 [8,] "DZA_2003_STEPS" "12"
 [9,] "DZA_2003_STEPS" "3" 
 [10,] "DZA_2003_STEPS" "3" 
 [11,] "DZA_2003_STEPS" "3" 
 [12,] "DZA_2003_STEPS" "3" 
 [13,] "DZA_2003_STEPS" "3" 
 [14,] "DZA_2003_STEPS" "6" 
 [15,] "DZA_2003_STEPS" "6" 
 [16,] "DZA_2003_STEPS" "3" 
 [17,] "DZA_2003_STEPS" "3" 
 [18,] "DZA_2003_STEPS" "6" 
 [19,] "DZA_2003_STEPS" "11"
 [20,] "DZA_2003_STEPS" "7" 

Answer 1

我已经颠倒了公式中变量的顺序，这似乎可以满足您的要求。

首先，提供一些数据准备代码，为其指定列名称并强制使用data.frame类。

colnames(steps) <- c("id_study", "edu")
steps <- as.data.frame(steps)

db2 <- aggregate (id_study ~ edu, data = steps, FUN = unique)
db2
#  edu       id_study
#1  11 DZA_2003_STEPS
#2  12 DZA_2003_STEPS
#3   3 DZA_2003_STEPS
#4   6 DZA_2003_STEPS
#5   7 DZA_2003_STEPS
#6   9 DZA_2003_STEPS