在Python中计算文件中单词的实例，仅适用于单个字母

Question

下面的代码应该计算文本文件中特定单词的实例，尽管它似乎仅适用于单个字母。 使用两个或两个以上字母的字符串总是返回0。我已经检查过了，对于给定的文件，我一直在使用的输入绝对不应该返回0。

有任何想法吗？

def count_of_word(filename, word_to_count):
    """Counts instances of a particular word in a file"""
    try:
        with open(filename) as file_object:
            contents = file_object.read()
    except FileNotFoundError:
        print("File " + filename + " not found")
    else:
        word_count = contents.lower().count(word_to_count)
        print("The count of the word  '" + word_to_count + "' in " + filename + " is " + str(word_count))

Answer 1

您将小写字母更改为仅文件输入。 尝试：

word_count = contents.lower().count(word_to_count.lower()) 

这对我的作品-我得到1026的计数and您参考的文件中。

编辑：怀疑编码问题，所以建议指定编码，它可以工作：

open(filename, encoding='utf_8') 

Answer 2

并没有更改代码中的一行，并且它起作用了，我想知道这是否与您如何将'the'或'and'传递到函数中有关，应该是count_of_word('alice.txt', 'the')

def count_of_word(filename, word_to_count):
    """Counts instances of a particular word in a file"""
    try:
        with open(filename) as file_object:
            contents = file_object.read()
    except FileNotFoundError:
        print("File " + filename + " not found")
    else:
        word_count = contents.lower().count(word_to_count)
        print("The count of the word  '" + word_to_count + "' in " + filename + " is " + str(word_count))

count_of_word('alice.txt', 'the')
count_of_word('alice.txt', 'a')

 ~/python/stack/sept/twenty_2$ python3.7 alice.py The count of the word 'and' in alice.txt is 2505 The count of the word 'a' in alice.txt is 9804