[英]Produce a per customer per month sales report via SQL eg group by two columns and sum the third
我很少写SQL(Azure SQL),但是我试图产生每个客户每月的销售总额。
顾客:
|Username |ID |
|user1 |1 |
|user2 |2 |
|user3 |3 |
订购:
|CustomerId |Month |Total |
|1 |1 |275 |
|1 |1 |10 |
|2 |1 |100 |
|1 |3 |150 |
|2 |2 |150 |
|2 |2 |65 |
|3 |2 |150 |
我想生产
|Username |Month1Total |Month2Total | Month3Total |
|user1 |285 |275 | 150 |
|user2 |100 |215 | 0 |
|user3 |0 |150 | 0 |
我可以做到以下几点
SELECT customerTable.Username Username, SUM(orderTable.OrderTotal) TotalMay
FROM "Order" orderTable
JOIN Customer customerTable ON orderTable.CustomerId = customerTable.Id
WHERE DATENAME(Month, (orderTable.PaidDateUTC)) = 'May'
GROUP BY Username
这将给我每月的输出。 但是我不知道如何循环播放,每月进行一次,然后按用户名分组。
如果您希望每个月都有单独的一列,请尝试此操作
SELECT customerTable.Username Username
,SUM(iif(ordertable.[month] = 1,orderTable.OrderTotal,0)) TotalJan
,SUM(iif(ordertable.[month] = 2,orderTable.OrderTotal,0)) TotalFeb
,SUM(iif(ordertable.[month] = 3,orderTable.OrderTotal,0)) TotalMar
,SUM(iif(ordertable.[month] = 4,orderTable.OrderTotal,0)) TotalApr
,SUM(iif(ordertable.[month] = 5,orderTable.OrderTotal,0)) TotalMay
FROM "Order" orderTable
JOIN Customer customerTable ON orderTable.CustomerId = customerTable.Id
GROUP BY Username
应该容易添加剩余的月份
您可以在以下情况下使用案例
with t1 as
( select o.CustomerId,o.Month, sum(Total) as total from
[Order]
group by o.CustomerId,o.Month
) select c.Username,
case when t1.month=1 then t1.total else 0 end month1,
case when t1.month=2 then t1.total else 0 end month2,
case when t1.month=3 then t1.total else 0 end month3
from t1 join Customer c on t1.CustomerId=c.ID
或者您可以使用PIVOT
select c.username, t.* from
(
select * from
(select * from ord
) src
pivot
( sum(Total) FOR Month IN ([1],[2],[3])
) pvt
) as t join Customer c on t.CustomerId=c.ID
像这样:
SELECT DATENAME(Month, (orderTable.PaidDateUTC)) MonthName,
customerTable.Username Username,
SUM(orderTable.OrderTotal) TotalMay
FROM "Order" orderTable
JOIN Customer customerTable ON orderTable.CustomerId = customerTable.Id
GROUP BY DATENAME(Month, (orderTable.PaidDateUTC)), Username
您只需要将月份名称从WHERE子句移至GROUP BY。
我只是用条件聚合来做JOIN
:
SELECT c.Username,
SUM(CASE WHEN o.Month = 1 THEN o.Total ELSE 0 END) AS [Month1Total],
SUM(CASE WHEN o.Month = 2 THEN o.Total ELSE 0 END) AS [Month2Total],
SUM(CASE WHEN o.Month = 3 THEN o.Total ELSE 0 END) AS [Month3Total],
. . .
FROM Customer C INNER JOIN
Order o
ON o.CustomerId = c.id
GROUP BY c.Username;
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