[英]How can I pad and/or truncate a vector to a specified length using numpy?
[英]How can i pad wav file to specific length?
我正在使用波形文件来制作不同长度的深度学习模型,所以我想使用 python 将它们全部填充到 16 秒长度
如果我理解正确,这个问题想要将所有长度固定到给定的长度。 因此,解决方案会略有不同:
from pydub import AudioSegment
pad_ms = 1000 # Add here the fix length you want (in milliseconds)
audio = AudioSegment.from_wav('you-wav-file.wav')
assert pad_ms > len(audio), "Audio was longer that 1 second. Path: " + str(full_path)
silence = AudioSegment.silent(duration=pad_ms-len(audio)+1)
padded = audio + silence # Adding silence after the audio
padded.export('padded-file.wav', format='wav')
这个答案与这个答案不同,因为这个答案从相同的长度创建所有音频,而另一个在最后添加相同大小的静音。
使用pydub :
from pydub import AudioSegment
pad_ms = 1000 # milliseconds of silence needed
silence = AudioSegment.silent(duration=pad_ms)
audio = AudioSegment.from_wav('you-wav-file.wav')
padded = audio + silence # Adding silence after the audio
padded.export('padded-file.wav', format='wav')
AudioSegment
对象是不可变的
您可以使用Librosa 。 L ibrosa.util.fix_length函数通过在包含音频数据的 numpy 数组的末尾附加零来向音频文件添加静音补丁:
from librosa import load
from librosa.util import fix_length
file_path = 'dir/audio.wav'
sf = 44100 # sampling frequency of wav file
required_audio_size = 5 # audio of size 2 second needs to be padded to 5 seconds
audio, sf = load(file_path, sr=sf, mono=True) # mono=True converts stereo audio to mono
padded_audio = fix_length(audio, size=5*sf) # array size is required_audio_size*sampling frequency
print('Array length before padding', np.shape(audio))
print('Audio length before padding in seconds', (np.shape(audio)[0]/fs))
print('Array length after padding', np.shape(padded_audio))
print('Audio length after padding in seconds', (np.shape(padded_audio)[0]/fs))
输出:
Array length before padding (88200,)
Audio length before padding in seconds 2.0
Array length after padding (220500,)
Audio length after padding in seconds 5.0
尽管在查看了许多类似的问题之后,似乎pydub.AudioSegment
是解决方案。
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