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将数字字符串列表转换为带有整数的元组 Python3

[英]Converting a list of strings of numbers to tuples with integers Python3

例子:

我的系统上保存了一个名为data.txt的文件。 该文件包含以下信息:

'Noah,14,233,66,21,88,42'
'Robert,34,11,667,2,785,23'
'Jackson,85,22,73,12,662,5'

等等,

我的问题是我怎样才能把它变成一个带整数的元组?,所以这是需要的:

('Noah', [14,233,66,21,88,42] ),
('Robert', [34,11,667,2,785,23] )

我假设您必须为每一行使用 for 循环,但我无法弄清楚。 任何帮助,将不胜感激!

如果您想要完全相同的输出,您可以在 上拆分每一行,并将其存储在一个元组中,

x = 'Noah,14,233,66,21,88,42'
# split string on , 
x = x.strip().split(',')
# x[0] is name, while x[1]....x[n] are numbers
y = (x[0], x[1:])
print(y)

输出,

('Noah', ['14', '233', '66', '21', '88', '42'])

显然你需要先分别从文件中读取每一行,所以,

with open("file_name", "r") as file:
    for line in file:
      line = line.strip().split(',')
      output = (line[0], line[1:])

将输出,

('Noah', ['14', '233', '66', '21', '88', '42'])
('Robert', ['34', '11', '667', '2', '785', '23'])
('Jackson', ['85', '22', '73', '12', '662', '5'])

同意其他人的观点,字典可能最适合这种情况,但这应该可以实现您的目标:

data= """Noah,14,233,66,21,88,42
Robert,34,11,667,2,785,23
Jackson,85,22,73,12,662,5"""

[(row.split(',')[0], row.split(',')[1:]) for row in data.split('\n')]

输出:

[('Noah', ['14', '233', '66', '21', '88', '42']),
('Robert', ['34', '11', '667', '2', '785', '23']),
('Jackson', ['85', '22', '73', '12', '662', '5'])]

假设文本与您在问题中所拥有的完全相同:

import re

input = """
'Noah,14,233,66,21,88,42'

'Robert,34,11,667,2,785,23'

'Jackson,85,22,73,12,662,5'
"""

lines = re.findall("'.*'", input) # Find lines which contain text between single quotes

tuples = []

for line in lines:
  line = line.replace("'", "").split(",") # Remove single quotes, split by comma
  tuples.append((line[0], line[1:])) # Add to tuple

print(tuples)

哪个会打印:

[
  ('Noah', ['14', '233', '66', '21', '88', '42']), 
  ('Robert', ['34', '11', '667', '2', '785', '23']), 
  ('Jackson', ['85', '22', '73', '12', '662', '5'])
]

首先,我们获取所有包含在两个单引号之间的行。 然后取出单引号并通过用逗号将其拆分来创建一个数组。 最后用第一个元素和第二个到最后一个元素的子数组创建一个元组。

你可以试试这个:

   with open(data.txt, 'r') as f:
        lines = [(line.strip().split(',')[0], line.strip().split(',')[1:])for line in f]
   print(lines)

它将以您描述的格式返回元组列表。

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