[英]Converting a list of strings of numbers to tuples with integers Python3
例子:
我的系統上保存了一個名為data.txt
的文件。 該文件包含以下信息:
'Noah,14,233,66,21,88,42'
'Robert,34,11,667,2,785,23'
'Jackson,85,22,73,12,662,5'
等等,
我的問題是我怎樣才能把它變成一個帶整數的元組?,所以這是需要的:
('Noah', [14,233,66,21,88,42] ),
('Robert', [34,11,667,2,785,23] )
我假設您必須為每一行使用 for 循環,但我無法弄清楚。 任何幫助,將不勝感激!
如果您想要完全相同的輸出,您可以在 上拆分每一行,
並將其存儲在一個元組中,
x = 'Noah,14,233,66,21,88,42'
# split string on ,
x = x.strip().split(',')
# x[0] is name, while x[1]....x[n] are numbers
y = (x[0], x[1:])
print(y)
輸出,
('Noah', ['14', '233', '66', '21', '88', '42'])
顯然你需要先分別從文件中讀取每一行,所以,
with open("file_name", "r") as file:
for line in file:
line = line.strip().split(',')
output = (line[0], line[1:])
將輸出,
('Noah', ['14', '233', '66', '21', '88', '42'])
('Robert', ['34', '11', '667', '2', '785', '23'])
('Jackson', ['85', '22', '73', '12', '662', '5'])
同意其他人的觀點,字典可能最適合這種情況,但這應該可以實現您的目標:
data= """Noah,14,233,66,21,88,42
Robert,34,11,667,2,785,23
Jackson,85,22,73,12,662,5"""
[(row.split(',')[0], row.split(',')[1:]) for row in data.split('\n')]
[('Noah', ['14', '233', '66', '21', '88', '42']),
('Robert', ['34', '11', '667', '2', '785', '23']),
('Jackson', ['85', '22', '73', '12', '662', '5'])]
假設文本與您在問題中所擁有的完全相同:
import re
input = """
'Noah,14,233,66,21,88,42'
'Robert,34,11,667,2,785,23'
'Jackson,85,22,73,12,662,5'
"""
lines = re.findall("'.*'", input) # Find lines which contain text between single quotes
tuples = []
for line in lines:
line = line.replace("'", "").split(",") # Remove single quotes, split by comma
tuples.append((line[0], line[1:])) # Add to tuple
print(tuples)
哪個會打印:
[
('Noah', ['14', '233', '66', '21', '88', '42']),
('Robert', ['34', '11', '667', '2', '785', '23']),
('Jackson', ['85', '22', '73', '12', '662', '5'])
]
首先,我們獲取所有包含在兩個單引號之間的行。 然后取出單引號並通過用逗號將其拆分來創建一個數組。 最后用第一個元素和第二個到最后一個元素的子數組創建一個元組。
你可以試試這個:
with open(data.txt, 'r') as f:
lines = [(line.strip().split(',')[0], line.strip().split(',')[1:])for line in f]
print(lines)
它將以您描述的格式返回元組列表。
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