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[英]Converting a list of strings of numbers to tuples with integers Python3
[英](Python) converting a list of integers into tuples/sets changes positions of integers
我想轉換
E =[1,6,1,7,2,3,2,6,3,2,3,8,4,5,4,7,5,4,5,9,6,1,6,7,6,2,7,1,7,6,7,4,8,9,8,3,9,8,9,5,]
進入
E = [{1,6},{1,7},{2,3},{2,6},{3,2},{3,8},{4,5},{4,7},{5,4},{5,9},{6,1},{6,7},{6,2},{7,1},{7,6},{7,4},{8,9},{8,3},{9,8},{9,5}
但我明白了
E=[[{1, 6}], [{1, 7}], [{2, 3}], [{2, 6}], [{2, 3}], [{8, 3}], [{4, 5}], [{4, 7}], [{4, 5}], [{9, 5}], [{1, 6}], [{6, 7}], [{2, 6}], [{1, 7}], [{6, 7}], [{4, 7}], [{8, 9}], [{8, 3}], [{8, 9}], [{9, 5}]]
相反,集合 {.} 中的順序也都被混淆了(順序不保留)。
為什么會這樣,我該如何解決?
我的代碼是:
def convert_to_set(x):
sets = []
l = len(x)
for i in range(0,l,2):
set1 = []
set1.append({x[i],x[i+1]})
sets.append(set1)
return sets
如果你想保留順序,你需要從set
切換到tuple
。 這樣做很容易:
list(zip(E[::2], E[1::2]))
這給你:
[(1, 6),
(1, 7),
(2, 3),
(2, 6),
(3, 2),
...
一種選擇如下:
sets = [{E[i],E[i+1]} for i in range(0,len(E)-1,2)]
此外,集合是無序的,因此您無法保留順序。
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