如何使用MOQ模拟时将Lazy的类对象类型传递给构造函数

Question

public class StudentTests
{
    private readonly Mock<IStudentRepository> studentRepository;
    private readonly Mock<Lazy<IDepartmentService>> departmentService;
    private readonly Mock<IStudentService> studentService;
    private readonly Student student;

    public StudentTests()
    {
        this.studentRepository = new Mock<IStudentRepository>();
        this.departmentService = new Mock<Lazy<IDepartmentService>>();
        this.studentService = new Mock<IStudentService>();

        this.student = new Student(departmentService.Object, studentRepository.Object, studentService.Object);
    }
}

上面的代码，其中IDepartmentService是Lazy类型，并且在将它传递给构造函数时它给出了错误。 通过“.Value”和MOQ使用“.Object”访问的Lazy类类型对象

先谢谢您的帮助！ 。

Answer 1

你不需要模拟Lazy对象，而是模拟对象Lazy返回，然后像这样手动创建Lazy ：

new Lazy<IDepartmentService>(() => departmentService.Object)

所以你得到：

private readonly Mock<IDepartmentService> departmentService; 
...
this.student = new Student(new Lazy<IDepartmentService>(() => departmentService.Object), studentRepository.Object, studentService.Object);