如何使用MOQ模擬時將Lazy的類對象類型傳遞給構造函數

Question

public class StudentTests
{
    private readonly Mock<IStudentRepository> studentRepository;
    private readonly Mock<Lazy<IDepartmentService>> departmentService;
    private readonly Mock<IStudentService> studentService;
    private readonly Student student;

    public StudentTests()
    {
        this.studentRepository = new Mock<IStudentRepository>();
        this.departmentService = new Mock<Lazy<IDepartmentService>>();
        this.studentService = new Mock<IStudentService>();

        this.student = new Student(departmentService.Object, studentRepository.Object, studentService.Object);
    }
}

上面的代碼，其中IDepartmentService是Lazy類型，並且在將它傳遞給構造函數時它給出了錯誤。 通過“.Value”和MOQ使用“.Object”訪問的Lazy類類型對象

先謝謝您的幫助！ 。

Answer 1

你不需要模擬Lazy對象，而是模擬對象Lazy返回，然后像這樣手動創建Lazy ：

new Lazy<IDepartmentService>(() => departmentService.Object)

所以你得到：

private readonly Mock<IDepartmentService> departmentService; 
...
this.student = new Student(new Lazy<IDepartmentService>(() => departmentService.Object), studentRepository.Object, studentService.Object);