根据ScatterPolar的颜色栏更改fillcolor

Question

我正在创建一个ScatterPolar图，其中附加了三个数字，并且我有第四个数字要确定fillcolor。 第四个数字可以介于0和1之间，并且色条显示该范围的色标。

我正在使用plotly 3.1.1和python版本3.6.3。

我无法弄清楚如何获得颜色条来影响fillcolor的颜色。 这是我到目前为止的内容：

import plotly.graph_objs as go
num_1 = 0.3
num_2 = 0.6
num_3 = 0.9
num_4 = 0.5

# Create radar plot
data = [go.Scatterpolar(
    r = [num_1, num_2, num_3],
    theta = ['number_1', 'number_2', 'number_3'],
    fill = 'toself',
    fillcolor = 'red', # I want this to change based on value of num_4
    opacity = 0.5,
    marker = dict(
        cmin = 0,
        cmax = 1,
        colorbar = dict(title='title'),
        colorscale = 'Viridis'
    ),
    mode = 'markers'
)]

# Create layout
layout = go.Layout(
    polar = dict(
        radialaxis = dict(visible = True, range = [0, 1])
    ),
    showlegend = False
)

# Plot data (using Jupyter notebook)
fig = go.FigureWidget(data=data, layout=layout)
fig

这是图像的输出，但是我希望根据num_4的值更改红色：

Answer 1

您可以使用matplotlib的颜色图来获取rgba值，可视化库通常具有相同的标准颜色图。

import plotly.graph_objs as go
from matplotlib import cm

num_1 = 0.3
num_2 = 0.6
num_3 = 0.9
num_4 = 0.5

cmap = cm.get_cmap('Viridis')

# Create radar plot
data = [go.Scatterpolar(
    r = [num_1, num_2, num_3],
    theta = ['number_1', 'number_2', 'number_3'],
    fill = 'toself',
    fillcolor = 'rgba' + str(cmap(num_4))
    opacity = 0.5,
    marker = dict(
        cmin = 0,
        cmax = 1,
        colorbar = dict(title='title'),
        colorscale = 'Viridis'
    ),
    mode = 'markers'
)]

# Create layout
layout = go.Layout(
    polar = dict(
        radialaxis = dict(visible = True, range = [0, 1])
    ),
    showlegend = False
)

# Plot data (using Jupyter notebook)
fig = go.FigureWidget(data=data, layout=layout)
fig