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[英]python: iterate through list and replace elements with corresponding dictionary values
[英]replace values of a dictionary with elements from a list in python
我有一个列表: operation = [5,6]
和字典dic = {0: None, 1: None}
我想用运算的值替换dic的每个值。
我尝试了此操作,但它似乎没有运行。
operation = [5,6]
for i in oper and val, key in dic.items():
dic_op[key] = operation[i]
有人有主意吗?
其他选择,也许是:
operation = [5,6]
dic = {0: None, 1: None}
for idx, val in enumerate(operation):
dic[idx] = val
dic #=> {0: 5, 1: 6}
在此使用索引的详细信息: 在“ for”循环中访问索引?
zip
方法可以胜任
operation = [5, 6]
dic = {0: None, 1: None}
for key, op in zip(dic, operation):
dic[key] = op
print(dic) # {0: 5, 1: 6}
上面的解决方案假定dic
被排序,以便operation
中的元素位置与dic
的键对齐。
在Python 3.7+中使用zip
,您可以执行以下操作:
operation = [5,6]
dic = {0: None, 1: None}
print(dict(zip(dic, operation)))
# {0: 5, 1: 6}
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