[英]Finding the sum of even valued terms in fibonacci sequence using for loop
斐波那契数列中的每个新项都是通过将前两项相加而生成的。 从 1 和 2 开始,前 10 项将是: 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ... 通过考虑斐波那契数列中值不超过的项四百万,求偶数值项的总和。
prev, cur = 0, 1
total = 0
while True:
prev, cur = cur, prev + cur
if cur >= 4000000:
break
if cur % 2 == 0:
total += cur
print(total)
我如何使用 for 循环解决这个问题?
斐波那契数列从第 34 个元素到达 4000000
prev, cur = 0, 1
total = 0
for i in range(34):
prev, cur = cur, prev + cur
if cur % 2 == 0:
total += cur
print(total)
first = 0
second = 1
for i in range(1,4000000):
next=(first+second)
print(next)
first=second
second=next
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