[英]Finding the sum of even valued terms in fibonacci sequence using for loop
斐波那契數列中的每個新項都是通過將前兩項相加而生成的。 從 1 和 2 開始,前 10 項將是: 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ... 通過考慮斐波那契數列中值不超過的項四百萬,求偶數值項的總和。
prev, cur = 0, 1
total = 0
while True:
prev, cur = cur, prev + cur
if cur >= 4000000:
break
if cur % 2 == 0:
total += cur
print(total)
我如何使用 for 循環解決這個問題?
斐波那契數列從第 34 個元素到達 4000000
prev, cur = 0, 1
total = 0
for i in range(34):
prev, cur = cur, prev + cur
if cur % 2 == 0:
total += cur
print(total)
first = 0
second = 1
for i in range(1,4000000):
next=(first+second)
print(next)
first=second
second=next
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.