使用字典键值对列表进行排序

Question

可以说我有一个清单

list_values = ['key3', 'key0', 'key1', 'key4', 'key2']

和命令的命令

ordered_dict = OrderedDict([('key4', 0), ('key1', 1), ('key2', 2), ('key0', 3), ('key3', 4)])

如何使用ordered_dict键对list_values进行排序？

即： sorted_list = ['key4', 'key1', 'key2', 'key0', 'key3']

编辑：由于几乎所有的答案都可以解决问题，什么是最合适，最完美的pythonic方法？

Answer 1

调用list.sort ，传递一个自定义key ：

list_values.sort(key=ordered_dict.get)    
list_values
# ['key4', 'key1', 'key2', 'key0', 'key3']

---

另外，非就地版本也可以使用

sorted(list_values, key=ordered_dict.get)
# ['key4', 'key1', 'key2', 'key0', 'key3']

Answer 2

如果我们假设列表是dict的子集：

list_values = ['key3', 'key1']

ordered_dict = OrderedDict([('key4', 0), ('key1', 1), ('key2', 2), ('key0', 3), ('key3', 4)])

output = [v for v in ordered_dict if v in list_values]

print(output)

→

['key1', 'key3']

范例2：

list_values = ['key3', 'key0', 'key1', 'key4', 'key2']

ordered_dict = OrderedDict([('key4', 0), ('key1', 1), ('key2', 2), ('key0', 3), ('key3', 4)])

output = [v for v in ordered_dict if v in list_values]

print(output)

→

['key4', 'key1', 'key2', 'key0', 'key3']