[英]Sort list of values in a dictionary
假设我有以下字典:
diction = {"string": ["alabama", "fruit", "emoji"], "number": [9, 13, 20]}
如何获得一个字典,其中“数字”键的值按降序排序,“字符串”应该按照排序的数字键排序? 字符串和数字键链接
我想得到
diction = {"string": ["emoji", "fruit", "alabama"], "number": [20, 13, 9]}
我很感激。
使用由diction['number']
选择的另一个列表排序:
diction["string"] = [x for _,x in sorted(zip(diction['number'],
diction['string']),
key=lambda pair: pair[0],
reverse=True)]
diction["number"] = sorted(diction["number"], reverse=True)
print (diction)
{'string': ['emoji', 'fruit', 'alabama'], 'number': [20, 13, 9]}
或使用pandas
:
import pandas as pd
d = pd.DataFrame(diction).sort_values('number', ascending=False).to_dict(orient='list')
print (d)
{'string': ['emoji', 'fruit', 'alabama'], 'number': [20, 13, 9]}
这是获得所需 output 的方法。
from collections import defaultdict
diction = {"string": ["alabama", "fruit", "emoji"], "number": [9, 13, 20]}
d = defaultdict(list)
for strng, num in zip(diction["string"], diction["number"]):
d[strng].append(num)
d = dict(sorted(d.items(), key=lambda x: x[1], reverse=True))
diction = {"string": [k for k in d.keys()], "number": [j[0] for j in d.values()]}
print(diction)
输出:
{'string': ['emoji', 'fruit', 'alabama'], 'number': [20, 13, 9]}
sorted
会正常工作。
diction["number"] = sorted(diction["number"])
对于将基于排序其中一个的重新排序对字典中的所有列表进行排序的通用方法,您可以以新的排序顺序构建索引列表并将其应用于所有列表:
diction = {"string": ["alabama", "fruit", "emoji"], "number": [9, 13, 20]}
keys = diction["number"] # list to sort
order = sorted(range(len(keys)),key=lambda i:keys[i],reverse=True) # indexes
for lst in diction.values():
lst[:] = [lst[i] for i in order] # apply new order to all lists
print(diction)
{'string': ['emoji', 'fruit', 'alabama'], 'number': [20, 13, 9]}
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