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[英]Can't go on clicking on the next page button while scraping certain fields from a website
[英]Can't keep clicking on the next page button while parsing the links
我用python与硒结合编写了一个脚本,单击“ search
按钮以填充结果,然后从其登录页面解析ya_result-item
类的不同链接,然后继续单击下一页按钮,同时解析其他链接直到没有更多按钮可点击为止。
但是,我的脚本只能解析第一页中的链接,然后单击下一页按钮一次,但随后卡住了。
在解析链接时,如何使脚本继续单击下一页按钮?
这是我的尝试:
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
url = "https://www.yogaalliance.org/Directory?Type=School"
def get_page_content(driver,link):
driver.get(link)
wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, "a.ya_directory-search-button"))).click()
while True:
for item in wait.until(EC.presence_of_all_elements_located((By.CSS_SELECTOR, "[id^='ya_result-item'] a[href^='/SchoolPublicProfile']"))):
print(item.get_attribute("href"))
try:
wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, "a[title*='next page']"))).click()
wait.until(EC.staleness_of(item))
except Exception:break
if __name__ == '__main__':
driver = webdriver.Chrome()
wait = WebDriverWait(driver,10)
get_page_content(driver,url)
我打印出异常,它说元素不可单击。 除了点击它,还可以使用send_keys("\\n")
模拟链接点击。
wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, "a[title*='next page']"))).send_keys("\n")
我尝试了一下,然后可以导航到所有页面。
如果您想抓取数据,则无需硒。 您可以使用requests
包更快地获取json格式的所有信息。
下面的代码收集所有学校的详细信息,作为result
的地图列表:
import requests
data = {
'take': '10',
'skip': '0',
'page': '1',
'pageSize': '10',
'pageIndex': '0'
}
url = 'https://www.yogaalliance.org/DesktopModules/YAServices/API/SchoolDirectory/SearchSchools'
response = requests.post(url, data=data)
result = response.json()["Result"]
totalCount = response.json()["TotalCount"]
totalCount = int(totalCount / 10)
for i in range(1, totalCount):
data['skip'] = int(data['skip']) + 10
data['page'] = i + 1
data['pageIndex'] = i
response = requests.post(url, data=data)
result.extend(response.json()["Result"])
print(result)
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