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[英]How can I assert calls that accept sequence arguments with Python Mock?
[英]Python - How can I assert a mock object was not called with specific arguments?
我意识到unittest.mock
对象现在有一个可用的assert_not_called
方法,但我正在寻找的是一个assert_not_called_with
。 有没有这样的东西? 我查看了 Google 并没有看到任何东西,当我尝试仅使用mock_function.assert_not_called_with(...)
它引发了一个AttributeError
,这意味着 function 不存在该名称。
with self.assertRaises(AssertionError):
mock_function.assert_called_with(arguments_I_want_to_test)
这行得通,但如果我想进行多个此类调用,则会使代码混乱。
您可以自己将assert_not_called_with
方法添加到unittest.mock.Mock
:
from unittest.mock import Mock
def assert_not_called_with(self, *args, **kwargs):
try:
self.assert_called_with(*args, **kwargs)
except AssertionError:
return
raise AssertionError('Expected %s to not have been called.' % self._format_mock_call_signature(args, kwargs))
Mock.assert_not_called_with = assert_not_called_with
以便:
m = Mock()
m.assert_not_called_with(1, 2, a=3)
m(3, 4, b=5)
m.assert_not_called_with(3, 4, b=5)
输出:
AssertionError: Expected mock(3, 4, b=5) to not have been called.
另一种使用模拟调用历史记录的解决方案:
from unittest.mock import call
assert call(arguments_I_want_to_test) not in mock_function.mock_calls
使用 Pytest,我断言调用了“AssertionError”:
import pytest
from unittest.mock import Mock
def test_something():
something.foo = Mock()
# Test that something.foo(bar) is not called.
with pytest.raises(AssertionError):
something.foo.assert_called_with(bar)
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