如何在csv文件中查找包含某行最高值的列名

Question

我试图在遍历每一行并从该行获取最高值后获取列标题，我该怎么做？

with open(filePath) as csvfile:
        reader = csv.DictReader(csvfile)
        for row in reader:        
            euro = int(row['Euro'])       
            usd = int(row['Usd']) 
            pound = int(row['Pound'])
            yuan= int(row['Yuan'])
            max_curr = max(euro,usd,pound,yuan)

例如。 对于第一行数据，我想打印标题“欧元”，因为 99 是该行中的最大值

对于第二行，我想打印标题“Usd”，因为 99 是该行中的最大值

Answer 1

使用max()函数中的key参数：

import csv
from collections import OrderedDict

with open(filePath) as csvfile:
    reader = csv.DictReader(csvfile)
    for row in reader:
        # converting the row values to integers.
        row = OrderedDict((k, int(v)) for k, v in row.items())
        # getting the column name of the max value
        max_curr = max(row, key=row.get)
        print(max_curr)

Answer 2

这是我的解决方案：

import csv

with open("/tmp/data.csv") as csvfile:
    reader = csv.DictReader(csvfile)
    for row in reader:
        max = -1
        for name in reader.fieldnames:
            v = int(row[name])
            if v > max:
                max = v
                maxname = name
        print(str(max) + ' ' + maxname)

对于输入：

Euro,Usd,Pound,Yuan
1,2,3,4
7,2,14,8
9,23,7,12
1,2,3,4

它产生：

4 Yuan
14 Pound
23 Usd
4 Yuan

当然，如果您不想，您不必打印该值。