[英]How i can remove the empty cells from my table view
我将自定义单元格用于表视图,根据我的代码,如果不满足任何条件,它将在表视图中添加一个空单元格或行。 我是iOS上的新手,请帮助我删除空白单元格。 这是我的代码段。
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let dict1 = arrMsg.object(at: indexPath.row) as! NSDictionary
let cell = tableView.dequeueReusableCell(withIdentifier: "Cell") as! ChatTableViewCell
let cell2 = tableView.dequeueReusableCell(withIdentifier: "Cell2") as! Chat2TableViewCell
if((String(describing: dict1.object(forKey: "SenderId")!)) == Auth.auth().currentUser?.uid && (ChatVC.selectedUser.replacingOccurrences(of: ".", with: "") == (String(describing: dict1.object(forKey: "ReceiverId")!))))
{
cell2.lblSender.text = (dict1.object(forKey: "Message") as! String)
cell2.lblSender.backgroundColor = UIColor(red: 0.09, green: 0.54, blue: 1, alpha: 1)
cell2.lblSender.font = UIFont.systemFont(ofSize: 18)
cell2.lblSender.textColor = .white
cell2.lblSender?.layer.masksToBounds = true
cell2.lblSender.layer.cornerRadius = 7
return cell2
}
else if ((String(describing: dict1.object(forKey: "ReceiverId")!)) == (Auth.auth().currentUser!.email?.replacingOccurrences(of: ".", with: ""))!)
{
cell.lblReceiver.text = (dict1.object(forKey: "Message") as! String)
cell.lblReceiver.backgroundColor = UIColor .lightGray
cell.lblReceiver.font = UIFont.systemFont(ofSize: 18)
cell.lblReceiver.textColor = UIColor.white
cell.lblReceiver?.layer.masksToBounds = true
cell.lblReceiver.layer.cornerRadius = 7
return cell
}
else {
let cell = UITableViewCell()
return cell
}
}
我认为这应该由TableView的DataSource清除,而不是必须处理cellForRowAt
中是否存在某些内容的逻辑。 您应该能够添加逻辑来根据您的arrMsg
对象查找每个节中的行数/有多少节
你需要
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let dict1 = arrMsg.object(at: indexPath.row) as! [String:Any]
let str = dict1["SenderId"] as! String
if str == Auth.auth().currentUser?.uid {
let cell2 = tableView.dequeueReusableCell(withIdentifier: "Cell2") as! Chat2TableViewCell
cell2.lblSender.text = (dict1.object(forKey: "Message") as! String)
cell2.lblSender.backgroundColor = UIColor(red: 0.09, green: 0.54, blue: 1, alpha: 1)
cell2.lblSender.font = UIFont.systemFont(ofSize: 18)
cell2.lblSender.textColor = .white
cell2.lblSender?.layer.masksToBounds = true
cell2.lblSender.layer.cornerRadius = 7
return cell2
}
else
{
let cell = tableView.dequeueReusableCell(withIdentifier: "Cell") as! ChatTableViewCell
cell.lblReceiver.text = (dict1.object(forKey: "Message") as! String)
cell.lblReceiver.backgroundColor = UIColor .lightGray
cell.lblReceiver.font = UIFont.systemFont(ofSize: 18)
cell.lblReceiver.textColor = UIColor.white
cell.lblReceiver?.layer.masksToBounds = true
cell.lblReceiver.layer.cornerRadius = 7
return cell
}
}
确保您的senderID应该是当前用户还是发送用户是您的工作,而不是nil,这将导致返回空单元格,也不要在Swift中使用NS
内容
转到情节提要中,在检查更改分隔符样式中从默认值或任何其他值中选择表视图
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