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[英]How to create a list that results a number from a given list, not the indices?
[英]How to create a list from results from a given list within a for loop?
我正在做 googles python 类。 并遇到了这个问题:
# A. match_ends
# Given a list of strings, return the count of the number of
# strings where the string length is 2 or more and the first
# and last chars of the string are the same.
# Note: python does not have a ++ operator, but += works.
我尝试了不同的方法,但似乎无法让它发挥作用。 这就是我现在得到的:
def match_ends(words):
words=sorted(words, key=len)
for i in words:
if len(i)<2:
print(i)
words=words[1:]
print(words)
for i in words:
if i[0:2]==i[-2:]:
x=[]
x.append[i]
这是怎么做的?
使用sum
和生成器表达式很容易完成:
def match_ends(words):
return sum(len(word) >= 2 and word[0] == word[-1] for word in words)
你可以简单地这样做:
def match_ends(words):
count = 0
for word in words:
if len(word) >= 2 and word[0] == word[-1]:
count += 1
return count
一个更pythonic的解决方案可能是
def func(s):
return len(s) >= 2 and s[0] == s[-1]
str_list = ['applea', 'b', 'cardc']
filtered_list = [s for s in str_list if (len(s) >= 2 and s[0] == s[-1])]
# or
filtered_list = list(filter(func, str_list))
count = len(filtered_list)
与之前的答案几乎相同,但 lambda
match_ends = lambda ws: sum(1 for w in ws if len(w)>1 and w[0] == w[-1])
或“扩展”形式
match_ends = lambda words: sum(1 for word in words if len(word)>1 and word[0] == word[-1])
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