python-如何解决必须是字符串而不是列表错误的python？

Question

我收到一个错误。“必须是str，而不是list”。

import os
import shutil


tesst = onlyfiles
tesst = []

with open('C:/Users/eGeneration Lab/Documents/project/try/data/final.txt') as f:
    found = 2
    for line in f:
        if tesst in onlyfiles: 

            found = 1

if found == 1:            
     shutil.move('C:/Users/eGeneration Lab/Documents/project/try/data/'+tesst,'C:/Users/eGeneration Lab/Documents/project/try/programs/error/'+tesst)

else:

    shutil.move('C:/Users/eGeneration Lab/Documents/project/try/data/'+tesst,'C:/Users/eGeneration Lab/Documents/project/try/programs/working/'+tesst)

    with open("C:/Users/eGeneration Lab/Documents/project/try/data/final.txt", "a") as f:
      f.write(tesst+"\n")

TypeError: must be str, not list

Answer 1

tesst = []
f.write(tesst+"\n") #Error occurs: TypeError: must be str, not list

f.write("".join(tesst)+"\n") # working [list to string]
f.write("\n".join(tesst)) #is better insert `\n`

Answer 2

如果您使用的是python3.6 +，则代码可以如下所示：

import shutil
from pathlib import Path

BASE_DIR = "C:/Users/eGeneration Lab/Documents/project/try"
data_path = Path(BASE_DIR) / "data"
error_path = Path(BASE_DIR) / "programs" / "error"
working_path = Path(BASE_DIR) / 'programs' / 'working'
final_file = data_path / "final.txt"

tesst = onlyfiles
tesst = []

with final_file.open() as fp:
    found = 2
    for line in fp:
        if tesst in onlyfiles:
            found = 1

if found == 1:
    shutil.move(data_path / tesst, error_path / tesst)
else:
    shutil.move(data_path / tesst, working_path / tesst)
    with final_file.open("a") as fp:
        fp.write(f"{tesst}\n")