[英]Convert a string to list of list of dicts python
我是python的新手。 我有一个字符串,取自我的sqlite数据库。 我想将字符串转换list of list of dicts
。 我尝试了ast
和json
库,但它失败了。
这是字符串:
a = '"[[{"plugin_type":"input","plugin":"mysql","dbname":"smackcoders","user":"root","password":"root","tbname":"agg_csv","host":"localhost","id":"mysql1","limit_count":5},{"plugin_type":"filter","plugin":"metrics","input_from":"mysql1","id":"metrics","field_name":"count_result", "field":"state","value":"kerala","action":"count","send_data_immediately":True},{"plugin_type":"output","plugin":"elastic","id":"elastic_search","input_from":"metrics","ind":"neww10","doc_typ":"sm23"}]]"'
这里我尝试的代码:
import ast
import json
a = '"[[{"plugin_type":"input","plugin":"mysql","dbname":"smackcoders","user":"root","password":"root","tbname":"agg_csv","host":"localhost","id":"mysql1","limit_count":5},{"plugin_type":"filter","plugin":"metrics","input_from":"mysql1","id":"metrics","field_name":"count_result", "field":"state","value":"kerala","action":"count","send_data_immediately":True},{"plugin_type":"output","plugin":"elastic","id":"elastic_search","input_from":"metrics","ind":"neww10","doc_typ":"sm23"}]]"'
a = a.replace("[[","[").replace("]]","]")
print(a)
# using json library- fails
# jdata = json.loads(a)
# for d in jdata:
# for key, value in d.iteritems():
# print (key, value)
#using ast library - it also fails
# res = [ast.literal_eval(x) for x in a]
我试过这个链接转换字符串到dict 并将str转换为列表列表
但就我而言,我有一个字符串list of list of dicts
其中包含字符串形式。 如何使它成为可能。
我希望输出相同,但它应该在dicts列表的列表中。
要求输出:
[[{"plugin_type":"input","plugin":"mysql","dbname":"smackcoders","user":"root","password":"root","tbname":"agg_csv","host":"localhost","id":"mysql1","limit_count":5},{"plugin_type":"filter","plugin":"metrics","input_from":"mysql1","id":"metrics","field_name":"count_result", "field":"state","value":"kerala","action":"count","send_data_immediately":True},{"plugin_type":"output","plugin":"elastic","id":"elastic_search","input_from":"metrics","ind":"neww10","doc_typ":"sm23"}]]
这应该工作。
import ast
a = '"[[{"plugin_type":"input","plugin":"mysql","dbname":"smackcoders","user":"root","password":"root","tbname":"agg_csv","host":"localhost","id":"mysql1","limit_count":5},{"plugin_type":"filter","plugin":"metrics","input_from":"mysql1","id":"metrics","field_name":"count_result", "field":"state","value":"kerala","action":"count","send_data_immediately":True},{"plugin_type":"output","plugin":"elastic","id":"elastic_search","input_from":"metrics","ind":"neww10","doc_typ":"sm23"}]]"'
print(ast.literal_eval(a.strip('"')))
输出:
[[{'dbname': 'smackcoders',
'host': 'localhost',
'id': 'mysql1',
'limit_count': 5,
'password': 'root',
'plugin': 'mysql',
'plugin_type': 'input',
'tbname': 'agg_csv',
'user': 'root'},
{'action': 'count',
'field': 'state',
'field_name': 'count_result',
'id': 'metrics',
'input_from': 'mysql1',
'plugin': 'metrics',
'plugin_type': 'filter',
'send_data_immediately': True,
'value': 'kerala'},
{'doc_typ': 'sm23',
'id': 'elastic_search',
'ind': 'neww10',
'input_from': 'metrics',
'plugin': 'elastic',
'plugin_type': 'output'}]]
您可以使用ast.literal_eval
。 您只需要确保可以解析您提供它的字符串。 在这种情况下,删除初始和最终引号就足够了:
from ast import literal_eval
literal_eval(a[1:-1]) # or strip('"') as in rakesh' answer
[[{'dbname': 'smackcoders',
'host': 'localhost',
'id': 'mysql1',
'limit_count': 5,
'password': 'root',
'plugin': 'mysql',
'plugin_type': 'input',
'tbname': 'agg_csv',
'user': 'root'},
{'action': 'count',
'field': 'state',
'field_name': 'count_result',
...
尝试这个。
a = '"[[{"plugin_type":"input","plugin":"mysql","dbname":"smackcoders","user":"root","password":"root","tbname":"agg_csv","host":"localhost","id":"mysql1","limit_count":5},{"plugin_type":"filter","plugin":"metrics","input_from":"mysql1","id":"metrics","field_name":"count_result", "field":"state","value":"kerala","action":"count","send_data_immediately":True},{"plugin_type":"output","plugin":"elastic","id":"elastic_search","input_from":"metrics","ind":"neww10","doc_typ":"sm23"}]]"'
a=a.strip('"')
a=eval(a)
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