如何将列表中的前三个元素作为列，其余作为行 - Python

Question

df = pd.DataFrame({'Categotry':['Food','Animal'],
          'Detail':[['Name','Color','Sweet?','Bread','Brown','No','Rice','White','No','Sushi','N/A','No'],
                    ['Name','Predator?','Habitat','Tigers','Yes','Forests','Lions','Yes','Savanna','Deers','No','Hardwoods']]})

我有上面的数据框，我想将 Detail 列拆分如下：

我怎样才能在 Python 中做到这一点？

谢谢您的帮助。

Answer 1

自定义功能

def process_details(details):
    cols, *data = np.reshape(details, (-1, 3))
    return pd.DataFrame(data, columns=cols)

我使用np.reshape因为我已经习惯了。 然而，这可以完成同样的事情。

def process_details(details):
    cols, *data = zip(*[iter(details)] * 3)
    return pd.DataFrame(data, columns=cols)

---

并排

因为列名不匹配

pd.concat({
    cat: process_details(details)
    for cat, details in zip(*map(df.get, df))
}, sort=False, axis=1)

   Animal                        Food              
     Name Predator?    Habitat   Name  Color Sweet?
0  Tigers       Yes    Forests  Bread  Brown     No
1   Lions       Yes    Savanna   Rice  White     No
2   Deers        No  Hardwoods  Sushi    N/A     No

但如果你坚持堆叠它们

pd.concat({
    cat: process_details(details)
    for cat, details in zip(*map(df.get, df))
}, sort=False)

            Name Predator?    Habitat  Color Sweet?
Animal 0  Tigers       Yes    Forests    NaN    NaN
       1   Lions       Yes    Savanna    NaN    NaN
       2   Deers        No  Hardwoods    NaN    NaN
Food   0   Bread       NaN        NaN  Brown     No
       1    Rice       NaN        NaN  White     No
       2   Sushi       NaN        NaN    N/A     No