从嵌套字典中获取具有最大值的键

Question

在此先感谢您的帮助。

我构建了以下代码（我尝试了以下代码，在字典中使用了字典）。

import operator
character = {'eyes_color':{"blue":10,"brown":12},
         'hair_color':{"black":15, "blonde":7},
         'gender': {"male":16,"female":6}
         }
maximun_key=max(character.items(), key=operator.itemgetter(1))[0]

如您所见，我在代码中使用了：

maximun_key=max(character.items(), key=operator.itemgetter(1))[0]

作为输出：

 brown male black 

即最大值，但是对于每个字典 。

在这种情况下，我希望输出如下：

male

我的意思是具有最大值的键 。

有谁知道我该如何解决这个问题？

Answer 1

您也可以使用map和functools.partial进行此操作。

vmax = partial(max, key=itemgetter(1))
vmax(map(vmax, map(dict.items, character.values())))[0]

它使用partial通过自定义键创建可重用的max函数，然后将dict.items映射到每个子dict，然后将dict.items映射到每个子dict，然后仅获取这些结果的最大值。

>>> from operator import itemgetter
>>> from functools import partial
>>> character = {'eyes_color':{"blue":10,"brown":12}, 'hair_color':{"black":15, "blonde":7}, 'gender': {"male":16,"female":6}}
>>> vmax = partial(max, key=itemgetter(1))
>>> max(map(vmax, map(dict.items, character.values())))[0]
male 

Answer 2

另一种方法-

使用lambda ：

character = {'eyes_color':{"blue":10,"brown":12},
         'hair_color':{"black":15, "blonde":7},
         'gender': {"male":16,"female":6}
         }

maximun_key= max([max(chars.items(),key = lambda x: x[1]) for chars in character.values()],key = lambda x: x[1])[0]

要么

使用operator.itemgetter ：

from operator import itemgetter
character = {'eyes_color':{"blue":10,"brown":12},
         'hair_color':{"black":15, "blonde":7},
         'gender': {"male":16,"female":6}
         }
maximun_key= max([max(chars.items(),key=itemgetter(1)) for chars in character.values()],key=itemgetter(1))[0]

Answer 3

使用以下代码获取结果：

import numpy as np
key_list, value_list = [], []
character = {'eyes_color':{"blue":10,"brown":12},
     'hair_color':{"black":15, "blonde":7},
     'gender': {"male":16,"female":6}
     }

for var in character.values():
    for i in var :
        key_list.append(i)
        value_list.append(var[i])

max_index = np.argmax(value_list)   #Getting index of maximum value
result = key_list[max_index]  #Getting result with the help of index value.
print(result)

产量

male

Answer 4

具有内置功能的简单方式：

d = {'eyes_color': {"blue": 10, "brown": 12},
     'hair_color': {"black": 15, "blonde": 7},
     'gender': {"male": 16, "female": 6}
     }

max_value, max_key = max(((v,k) for inner_d in d.values() for k,v in inner_d.items()))
print(max_key)   # male
print(max_value) # 16