如何计算文本文件中值匹配的出现次数

Question

这是我的问题：每个员工都由一个 ID 唯一标识（例如 KCUTD_41）我已经从一个文件中创建了一个字典来收集每个公司的员工 ID，如下所示：

{    'Company 1' :['KCUTD_41',
                   'KCTYU_48',
                   'VTSYC_48',
                      ......]
     'Company 2' :['PORUH_21',
                   'PUSHB_10',
                    ....... ]
     'Company 3' :['STEYRU_69']}

我总共有几家公司。

在另一个文件中并行，我有几行，其中每一行对应于具有多个员工和博士生的公司之间的协作组（d215485 等.....）

该文件如下所示：

PORUH_21 d215487 d215489 d213654 KCTYU_48 d154225 ...
d25548 d89852 VTSYC_48 d254548 d121154 d258774 PUSHB_10 ...
etc ....

我想要的是员工人数和组数（出现的行）以获得类似的东西

OUTPUT：

Company 1 : (number of employees from company 1 per line ) : number of groups or line where it appears in total 
Company 2 : (number of employees per line from company2) : nb of groups or line where the employees from company2 appears in total
Company 3 : ......

我想使用一个条件来查看我的字典中每个键的值是否匹配，如果是，则计算出现次数

我希望它现在更好^^'

如果你能帮助我^^

Answer 1

我不清楚你希望 output 看起来如何，但这段代码可能会帮助你到达你想要 go 的地方......

import re

companies = {
    'Company 1' :['KCUTD_41','KCTYU_48','VTSYC_48'],
    'Company 2' :['PORUH_21','PUSHB_10'],
    'Company 3' :['STEYRU_69']
     }

finalout = {}
for k,v in companies.items():
    finalout[k] = {"number_in_company":len(v)}
print (finalout)

lines_from_file = [
    "PORUH_21 d215487 d215489 d213654 KCTYU_48 d154225", 
    "d25548 d89852 VTSYC_48 d254548 d121154 d258774 PUSHB_10"
]


pattern_groups    = "(d\d+)"
pattern_employees = "([A-Z]_\d+)"
for line in lines_from_file:
    print("---------------------")
    print(line)
    print("Groups per line:", re.subn(pattern_groups, '', line)[1])
    print("Employees per line:", re.subn(pattern_employees, '', line)[1])

OUTPUT：

{'Company 1': {'number_in_company': 3}, 'Company 2': {'number_in_company': 2}, 'Company 3': {'number_in_company': 1}}
---------------------
PORUH_21 d215487 d215489 d213654 KCTYU_48 d154225
Groups per line: 4
Employees per line: 2
---------------------
d25548 d89852 VTSYC_48 d254548 d121154 d258774 PUSHB_10
Groups per line: 5
Employees per line: 2