如何計算文本文件中值匹配的出現次數

Question

這是我的問題：每個員工都由一個 ID 唯一標識（例如 KCUTD_41）我已經從一個文件中創建了一個字典來收集每個公司的員工 ID，如下所示：

{    'Company 1' :['KCUTD_41',
                   'KCTYU_48',
                   'VTSYC_48',
                      ......]
     'Company 2' :['PORUH_21',
                   'PUSHB_10',
                    ....... ]
     'Company 3' :['STEYRU_69']}

我總共有幾家公司。

在另一個文件中並行，我有幾行，其中每一行對應於具有多個員工和博士生的公司之間的協作組（d215485 等.....）

該文件如下所示：

PORUH_21 d215487 d215489 d213654 KCTYU_48 d154225 ...
d25548 d89852 VTSYC_48 d254548 d121154 d258774 PUSHB_10 ...
etc ....

我想要的是員工人數和組數（出現的行）以獲得類似的東西

OUTPUT：

Company 1 : (number of employees from company 1 per line ) : number of groups or line where it appears in total 
Company 2 : (number of employees per line from company2) : nb of groups or line where the employees from company2 appears in total
Company 3 : ......

我想使用一個條件來查看我的字典中每個鍵的值是否匹配，如果是，則計算出現次數

我希望它現在更好^^'

如果你能幫助我^^

Answer 1

我不清楚你希望 output 看起來如何，但這段代碼可能會幫助你到達你想要 go 的地方......

import re

companies = {
    'Company 1' :['KCUTD_41','KCTYU_48','VTSYC_48'],
    'Company 2' :['PORUH_21','PUSHB_10'],
    'Company 3' :['STEYRU_69']
     }

finalout = {}
for k,v in companies.items():
    finalout[k] = {"number_in_company":len(v)}
print (finalout)

lines_from_file = [
    "PORUH_21 d215487 d215489 d213654 KCTYU_48 d154225", 
    "d25548 d89852 VTSYC_48 d254548 d121154 d258774 PUSHB_10"
]


pattern_groups    = "(d\d+)"
pattern_employees = "([A-Z]_\d+)"
for line in lines_from_file:
    print("---------------------")
    print(line)
    print("Groups per line:", re.subn(pattern_groups, '', line)[1])
    print("Employees per line:", re.subn(pattern_employees, '', line)[1])

OUTPUT：

{'Company 1': {'number_in_company': 3}, 'Company 2': {'number_in_company': 2}, 'Company 3': {'number_in_company': 1}}
---------------------
PORUH_21 d215487 d215489 d213654 KCTYU_48 d154225
Groups per line: 4
Employees per line: 2
---------------------
d25548 d89852 VTSYC_48 d254548 d121154 d258774 PUSHB_10
Groups per line: 5
Employees per line: 2