繁体   English   中英

我有两个数据框(DF1)和(DF2)。 我想替换 (DF2) 中与 (DF1) 的两列上的条件匹配的列的值

[英]I have two dataframes (DF1) and (DF2). I want to substitute values for a column in (DF2) that match criteria on two columns of (DF1)

我想用 DataFrame2 (DF2) 中的相应“Salary”填充 DataFrame1 (DF1) 中的“Salary”列。 这些需要匹配“团队”和“球员”。

要注意:

数据框是: 大小不同。 不是同一个顺序。

import pandas as pd


#df 1:

nba_data = {'Team': ['Mavericks', 'Mavericks', 'Mavericks', '', 'NewYorkKnicks17','Houston Rockets', 'NewYorkKnicks17'], 
            'Players': ['Luka Doncic', 'Kristaps Porzingis', 'Jalen Brunson', 'Kristaps Porzingis', 'JR Smith',
                        'James Harden', 'Derrick Rose',],
            'Salary': ['0', '0', '0','0', '0', '0', '0'],
           'Coach': ['Rick Carlisle', 'Rick Carlisle', 'Steve Kerr', 'Phil Jackson', 'Tom Thibideou', '', '']}

nba_df1 = pd.DataFrame(nba_data)

nba_df1


#df2:

nba_data2 = {'Team': ['Mavericks', 'Mavericks', 'Mavericks', 'NewYorkKnicks17', 'NewYorkKnicks17', 'NewYorkKnicks17', 'Houston Rockets'], 
            'Players': ['Luka Doncic', 'Kristaps Porzingis', 'Steph Curry', 'JR Smith', 'Derrick Rose',
                        'Kristaps Porzingis', 'James Harden'],
            'Salary': ['3m', '126m', '0','115m', '0', '20m', '1.5m'],
            'Coach': ['Rick Carlisle', 'Rick Carlisle', 'Steve Kerr', '', 'Tom Thibideou', 'Phil Jackson', '']}


nba_df2 = pd.DataFrame(nba_data2)

nba_df2

所需的结果 = nba_df1 并填充了适当的薪水(运行以下命令):

nba_data3 = {'Team': ['Mavericks', 'Mavericks', 'Mavericks', '', 'NewYorkKnicks17','Houston Rockets', 'NewYorkKnicks17'], 
            'Players': ['Luka Doncic', 'Kristaps Porzingis', 'Jalen Brunson', 'Kristaps Porzingis', 'JR Smith',
                        'James Harden', 'Derrick Rose',],
            'Salary': ['3m', '126m', '0','20m', '115m', '1.5m', '0'],
           'Coach': ['Rick Carlisle', 'Rick Carlisle', 'Steve Kerr', 'Phil Jackson', 'Tom Thibideou', '', '']}



nba_df1_adjusted = pd.DataFrame(nba_data3)






Kindly note: this is not a tutorial. - it is a specific question and therefore not a duplicate of a general tutorial. 
agg = pd.merge(nba_df1, nba_df2, on = ['Players', 'Team'], how = 'left')

您的结果将在 Salary_y 上

编辑:有点脏,但它有效:

agg = pd.merge(nba_df1, nba_df2[['Team', 'Players', 'Salary']], on = ['Players', 'Team'], how = 'left')
agg2 = pd.merge(nba_df1, nba_df2, on = ['Players', 'Coach'], how = 'left')

merge = pd.merge(agg, agg2, on = ['Players', 'Coach'])

merge['Salary'] = merge['Salary_y_x'].fillna(merge['Salary_y_y'])

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM