[英]What's the difference between list1 = [] list2 = [] and list1 = list2 = [] in python?
[英]for any item of list1 if it is list2 in python
根据此问题检查 Python 列表项是否包含另一个字符串中的字符串,在第一个答案中,我想在列表中循环,而不是字符串
我已经尝试过了,但它没有用
matching = [s for s in fd if [s for s in chht] in fd]
更多声明
我有列表 1=["he","bell","go"] list=["o","e"]
所以实际的 output 是:
单词有 o 字母是 ["go"]
单词有 e 字母是 ["he","bell"]
尝试使用any
:
matching = any([s in chht for s in fd])
wordList = ["he", "bell", "go"] searchCharList = ["o", "e"] matching = [word for word in wordList for char in searchCharList if char in word] print matching >>> ['he', 'bell', 'go'] print bool(matching) >>> True
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