for any item of list1 if it is list2 in python

Question

Check if a Python list item contains a string inside another string according to this question and in first answer, instead of a string, I want to loop in list

I have tried this but it didn't work

matching = [s for s in fd if [s for s in chht] in fd]

for more declare

I have list 1=["he","bell","go"] list=["o","e"]

so the actual output is:

words has o letter are ["go"]

words has e letter are ["he","bell"]

Answer 1

Try using any :

matching = any([s in chht for s in fd])

Answer 2

wordList = ["he", "bell", "go"] searchCharList = ["o", "e"] matching = [word for word in wordList for char in searchCharList if char in word] print matching >>> ['he', 'bell', 'go'] print bool(matching) >>> True