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[英]How to add repeats of the same element to list by comparing index in Python?
[英]How to find the index of a list element by comparing it to a string in Python?
假设我有一个包含一些文件的列表,如下所示:
file_list = ['folder\\text.txt', 'folder\\data.csv', 'folder\\picture.png']
并且还声明了一个字符串:
file = 'text.txt' #Did not include 'folder\\', intentionally.
如何使用“文件”变量获取 file_list 的索引?
我尝试了以下方法:
index = file_list.index(file)
filename = file_list[index]
print(filename)
但是,我得到了这个结果:
ValueError: 'text.txt' is not in list
我已经理解为什么我的解决方案失败了,但是是否有一个有效的解决方案可以通过使用字符串变量来获取索引?
这将帮助你:)
file_list = ['folder\\text.txt', 'folder\\data.csv', 'folder\\picture.png']
file = 'data.csv'
flag = True
for i in range(len(file_list)):
if(file_list[i].find(file)!=-1):
print("file found at {} position in the list".format(i))
flag = False
break
if flag:
print ("File not found :(")
OUTPUT:
file found at 0 position in the list
鉴于您不想使用os
模块(正如您在评论中所说),只需实现一个基于 split 的基本基本basename
func。
然后,您可以使用简单的理解来创建一个仅包含文件名的匹配列表,并在其中查找索引。
def basename(path):
return path.split('\\')[-1]
file_list = ['folder\\text.txt', 'folder\\data.csv', 'folder\\picture.png']
file = 'text.txt'
file_basename_list = [basename(f) for f in file_list]
index = file_basename_list.index(file)
filename = file_list[index]
print(filename)
Output:
folder\text.txt
您应该检查file_list
的每个元素以找出file
的索引:
def find_index(file, file_list):
for idx, file_name in enumerate(file_list):
if file in file_name:
print(f"idx:{idx}, file_name:{file_name}")
return idx
if __name__ == '__main__':
file_list = ['folder\\text.txt', 'folder\\data.csv', 'folder\\picture.png']
file = 'text.txt'
idx = find_index(file, file_list)
if idx:
print(file_list[idx])
else:
print(f"Couldn't find idx of {file} ")
Output:
idx:0, file_name:folder\text.txt
folder\text.txt
直接的方法是:
file_list = ['folder\\text.txt', 'folder\\data.csv', 'folder\\picture.png']
search_file = 'text.txt'
base_path = "folder\\"
def find_file(file_list, search_file, base_path):
for idx, file in enumerate(file_list):
if file == base_path+search_file:
return idx
return "File Not Found"
print(find_file(file_list, search_file, base_path))
如果要动态添加base_path
,请使用:
import os.path
path = 'folder\\'
base_path = os.path.basename(path)
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