为什么 GetSystemInfo().minimumApplicationAddress 返回的数字大于 GetSystemInfo().maximumApplicationAddress？

Question

我正在学习有关如何操作内存的教程，无论出于何种原因，以下代码为 minimumAddress 提供了 65536，为最大地址提供了 -65537，这没有多大意义。

我希望最大地址大于最小值，否则将意味着没有地址。

这是我正在关注的教程的链接，以防万一。

SYSTEM_INFO sys_info = new SYSTEM_INFO();
GetSystemInfo(out sys_info);

IntPtr proc_min_address = sys_info.minimumApplicationAddress;
IntPtr proc_max_address = sys_info.maximumApplicationAddress;

// saving the values as long ints so I won't have to do a lot of casts later

long proc_min_address_l = (long)proc_min_address;
long proc_max_address_l = (long)proc_max_address;

Console.WriteLine("Min Addr: {0}, Max Addr: {1}", proc_min_address_l, proc_max_address_l);

Answer 1

sys_info.maximumApplicationAddress根据平台类型更改：
任何 CPU：0xffffeffff
x64：0x00007ffffffffff
x86：0x7ffeffff

在进行 long 类型转换时，您正在转换 4 字节的带符号值 (int32)，即 0xfffeffff，即 -65537。

由于使用内存地址不会有任何负值，因此您可以更改为无符号值。

IntPtr 到 UIntPtr

长到乌龙

public struct SYSTEM_INFO { ... public UIntPtr minimumApplicationAddress; public UIntPtr maximumApplicationAddress; ... } public static void Main() { SYSTEM_INFO sys_info = new SYSTEM_INFO(); GetSystemInfo(out sys_info); UIntPtr proc_min_address = sys_info.minimumApplicationAddress; UIntPtr proc_max_address = sys_info.maximumApplicationAddress; // saving the values as ulong ints so I won't have to do a lot of casts later ulong proc_min_address_l = (ulong)proc_min_address; ulong proc_max_address_l = (ulong)proc_max_address; Console.WriteLine("Min Addr: {0}, Max Addr: {1}", proc_min_address_l, proc_max_address_l); }