Python从请求响应中跳过标题行

Question

我正在查询服务以获取 csv 数据，我想通过跳过标题信息代码将此 csv 提取附加到另一个文件中 -

response = requests.get('http://myservice.com&format=csv')
with open('out.csv', 'a', new like='') as f:
   writer = csv.writer(f)
   for line in response.iter_lines():
        next(line)
        writer.writerow(line.decode('utf-8').split('|'))

尝试了上述但我收到错误

'bytes' 对象不是迭代器

Answer 1

response.iter_lines()是迭代器， lines是迭代的值。 所以调用next()没有多大意义。

你可以：

iter_lines = response.iter_lines()
next(iter_lines, None)
for line in iter_lines:
    writer.writerow(line.decode('utf-8').split('|'))

您也可以尝试直接读入csv.DictReader ，例如：

response = requests.get('http://myservice.com&format=csv')
with open('out.csv', 'a') as f:
    reader = csv.DictReader(response.text.splitlines(), delimiter='|')
    writer = csv.DictWriter(f, reader.fieldnames)
    writer.writerows(reader)

Answer 2

试试

response = 
requests.get('http://myservice.com&format=csv')
with open('out.csv', 'a', new like='') as f:
    writer = csv.writer(f)
    rows = response.iter_lines()
    next(rows)
    for line in rows:
        writer.writerow(line.decode('utf-8').split('|'))

rows是需要跳过标题的迭代器，而line是每行读取的实际内容。

for循环简单地遵循迭代协议，即

• 它通过在对象上调用iter获得一个迭代器（一个迭代器返回自身，在这种情况下）
• 它不断调用next直到引发StopIteration异常