在 Python 中将包含元组列表的字典转换为 DataFrame

Question

我正在尝试将具有元组列表作为值的 2 键字典转换为 Pandas DataFrame。 我正在处理的数据如下所示：

dictionary={'Week':[(week1,week2),(week3,week4)],'Numbers':[(number1,number2),(number3,number4)]}

反正有没有把它转换成一个看起来像的熊猫数据帧：

Week   Numbers
week1  number1
week2  number2
week3  number3
week4  number4

我曾尝试使用pandas.DataFrame(dictionary)将字典强制转换为 DataFrame，但我最终得到一行有两个非常宽的列。 任何指导将不胜感激！

Answer 1

您可以使用itertools.chain.from_iterable来展平每个键的元组并调用数据帧构造函数：

import itertools
df = pd.DataFrame({k: [*itertools.chain.from_iterable(v)] for k,v in dictionary.items()})

---

    Week  Numbers
0  week1  number1
1  week2  number2
2  week3  number3
3  week4  number4

Answer 2

您可以使用.explode()函数（从 0.25.0+ 版本开始）：

dictionary={'Week':[('week1','week2'),('week3','week4')],'Numbers':[('number1','number2'),('number3','number4')]}
df = pd.DataFrame(dictionary)
print(pd.concat([df.explode('Week')['Week'], df.explode('Numbers')['Numbers']], axis=1))

印刷：

    Week  Numbers
0  week1  number1
0  week2  number2
1  week3  number3
1  week4  number4

Answer 3

仅使用列表理解：

dictionary={'Week':[('week1','week2'),('week3','week4')],'Numbers':[('number1','number2'),('number3','number4')]}
pd.DataFrame({
    k: [t for tup in value for t in tup] for k, value in dictionary.items()
})

或ndarray.flatten ：

pd.DataFrame({
    k: np.array(value).flatten() for k, value in dictionary.items()
})