[英]Selecting an ID which matches a user input in SQLite3 Python
我想给用户一个选项来选择一个 ID 来查看 matplotlib 报告......但是,我坚持选择类别与用户输入匹配的数据(id_input)
if report_option == "A":
print("Expense Report by Category: \n")
id_input = input("Please enter the ID of the Category you would like to view: \n")
c.execute("SELECT * FROM tblCategory")
for row in c.fetchall():
print(row)
c.execute('SELECT CategoryID, AmountSpent FROM tblFinance')
categories = []
amountspent = []
for row in c.fetchall():
print(row[0])
categories.append(row[0])
amountspent.append(row[1])
plt.plot(categories, amountspent)
plt.ylabel('Amount Spent')
plt.xlabel('Category ID')
plt.show()
menu()
任何帮助将不胜感激!
我假设您尝试从tblFinance
中选择AmountSpent
,其中CategoryID
是用户输入的内容。
id_input = input("Please enter the ID of the Category you would like to view: \n")
data = []
for row in c.execute("SELECT AmountSpent FROM tblFinance WHERE CategoryID=?", (id_input, )):
data.append(row)
return data #use data variable here however you need with matplotlib
解释:
您要创建一个 SELECT x FROM y WHERE z = a 语句,该语句从表 y 中选择 x,其中 z 是 a。 基本上就是它所说的。 你可以用?
以及根据输入获取数据的第二个参数。 如果您有更多问题,请告诉我。
编辑:
如果您想同时选择 AmountSpent 和 CategoryID,请将 SQL 语句替换为"SELECT CategoryID, AmountSpent FROM tblFinance WHERE CategoryID=?"
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