如何根据主机名每小时计算平均disk_available，python

Question

结果数据：

<QuerySet [{'disk_available': 26, 'hostname': '2', 'day': datetime.datetime(2020, 2, 11, 0, 0, tzinfo=<UTC>), 'c': 354}, {'disk_available': 27, 'hostname': '2', 'day': datetime.datetime(2020, 2, 10, 0, 0, tzinfo=<UTC>), 'c': 273}, {'disk_available': 19, 'hostname': '2', 'day': datetime.datetime(2020, 2, 12, 0, 0, tzinfo=<UTC>), 'c': 12}, {'disk_available': 26, 'hostname': '2', 'day': datetime.datetime(2020, 2, 12, 0, 0, tzinfo=<UTC>), 'c': 45}, {'disk_available': 26, 'hostname': 'tes', 'day': datetime.datetime(2020, 2, 11, 0, 0, tzinfo=<UTC>), 'c': 1945}, {'disk_available': 19, 'hostname': 'tes', 'day': datetime.datetime(2020, 2, 12, 0, 0, tzinfo=<UTC>), 'c': 53}, {'disk_available': 1, 'hostname': 'tes', 'day': datetime.datetime(2020, 2, 11, 0, 0, tzinfo=<UTC>), 'c': 1}, {'disk_available': 26, 'hostname': 'tes', 'day': datetime.datetime(2020, 2, 12, 0, 0, tzinfo=<UTC>), 'c': 45}, {'disk_available': 27, 'hostname': 'tes', 'day': datetime.datetime(2020, 2, 10, 0, 0, tzinfo=<UTC>), 'c': 291}]>

Answer 1

SocketClient.objects.annotate(day=TruncDay('create')).values('day').annotate(c=Count('id')).values('day', 'disk_available', 'hostname', 'c').order_by('hostname') 

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从上面的结果我想这样做，我想每小时显示主机名的平均结果