设置seaborn图的字体大小

Question

我正在努力正确设置seaborn图的字体大小。 设置标题的字体大小工作得很好，但不幸的是，关于轴和图例的字体大小，我还没有取得任何成功。 这是我的代码（使用一些虚拟数据）：

import matplotlib.pyplot as plt
import pandas as pd
import seaborn as sns

df = pd.DataFrame()
df['First PCA dimension'] = [1,2,3,4]
df['Second PCA dimension'] = [0,5,5,7]
df['Third PCA dimension'] = [1,2,6,4]
df['Data points'] = [1,2,3,4]

plt.figure(figsize=(42,30))
plt.title('2-D PCA of my data points',fontsize=32)

colors = ["#FF9926", "#2ACD37","#FF9926", "#FF0800"]
sns.scatterplot(x="First PCA dimension", y="Second PCA dimension", hue="Data points", palette=sns.color_palette(colors), data=df, legend="full", alpha=0.3)
sns.set_context("paper", rc={"font.size":48,"axes.titlesize":48,"axes.labelsize":48})   
plt.savefig(outputPath+'/PCA/'+'PCA_2D.png',dpi=100,bbox_inches='tight')

，这会导致以下输出：

更改“set_context”函数中的数字没有任何效果。

Answer 1

顺便说一句，图形尺寸太大(42x30) ：

import matplotlib.pyplot as plt
import pandas as pd
import seaborn as sns

df = pd.DataFrame()
df['First PCA dimension'] = [1,2,3,4]
df['Second PCA dimension'] = [0,5,5,7]
df['Third PCA dimension'] = [1,2,6,4]
df['Data points'] = [1,2,3,4]

plt.figure(figsize=(42,30))
plt.title('2-D PCA of my data points',fontsize=32)

colors = ["#FF9926", "#2ACD37","#FF9926", "#FF0800"]
b = sns.scatterplot(x="First PCA dimension", y="Second PCA dimension", hue="Data points", palette=sns.color_palette(colors), data=df, legend="full", alpha=0.3)
sns.set_context("paper", rc={"font.size":48,"axes.titlesize":48,"axes.labelsize":48})

b.set_ylabel('mylabely', size=54)
b.set_xlabel('mylabelx', size=54)
b.set_xticklabels([1,2,3,4,5,6,7,8], fontsize = 36)

lgnd = plt.legend(fontsize='22')
for handle in lgnd.legendHandles:
    handle.set_sizes([26.0])

plt.show()