[英]Compare list item with a dictionary key and print out the value of the key if the item exists in the dictionary
示例代码:
my_dict = {'ABC':'Apple','DEF':'Mango','GHI':'Pear','JKL':'Orange','MNO':'Plum'}
lst_x = ['DEF','GHI']
预期结果:
['Mango', 'Pear']
您可以使用operator.itemgetter
一次检索多个键:
from operator import itemgetter
my_dict = {'ABC':'Apple','DEF':'Mango','GHI':'Pear','JKL':'Orange','MNO':'Plum'}
lst_x = ['DEF','GHI']
# in case, if there's a chance, that lst_x would get some of the keys, that are not in my_dict - add the below line:
# lst_x=set(lst_x).intersection(set(my_dict.keys()))
res=itemgetter(*lst_x)(my_dict)
输出:
>>> res
('Mango', 'Pear')
你可以使用一个简单的循环,询问是否有一个具有相同值的键并打印它,例如:
my_dict = {'ABC':'Apple','DEF':'Mango','GHI':'Pear','JKL':'Orange','MNO':'Plum'}
lst = ['ABC','DEF','GHI','JKL','MNO']
for key in lst:
if key in my_dict.keys():
print(key, '->' , my_dict[key])
>>> ABC -> Apple
>>> DEF -> Mango
>>> GHI -> Pear
>>> JKL -> Orange
>>> MNO -> Plum
一种方法是使用list comprehension
来构建请求的列表。
本质上,我们在外循环中遍历list
,在内循环中遍历dictionary
,然后将list
值与dictionary
的key
进行比较,如果匹配,则将关联key
的值保存在新的输出列表。
下面的代码片段按上述方式工作:
my_dict = {'ABC':'Apple','DEF':'Mango','GHI':'Pear','JKL':'Orange','MNO':'Plum'}
lst_x = ['DEF','GHI']
out = [value for element in lst_x for key, value in my_dict.items() if element == key]
print(out)
运行时打印:
['Mango', 'Pear']
我个人不相信给出直接的答案,所以我会给你一个提示:
// for x in lst:
// if x in dictionary then
// lst_x.append(x)
我相信这应该足以让你弄清楚其余的。
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