[英]Extracting part of name from string
我试图从包含全名格式的 Name 列中提取 lastName、firstName、middleName。
这是我试图提取的示例名称:
DELA CRUZ, JUAN PONCE SR. ENRILE
ATIENZA, ROBERTO JR. SANTO
GONZA, MARK ANTHONY, DELLY-LO
我想像这样提取它们:
LastName | FirstName | MiddleName
DELA CRUZ | JUAN PONCE SR. | ENRILE
ATIENZA | ROBERTO JR. | SANTOS
GONZA | MARK ANTHONY | DELLY
到目前为止,这是我的脚本
DECLARE @Name VARCHAR(50) = 'DELA CRUZ, JUAN PONCE SR. ENRILE'
SELECT
SUBSTRING(@Name, 0, CharIndex(',', @Name)) LastName,
REVERSE(LEFT(REVERSE(@Name), CharIndex(' ', reverse(@Name))-1)) MiddleName
我在使用 -LO 后缀提取中间时也遇到问题。
谢谢你
试试下面的逻辑(修改你的)
DECLARE @Name VARCHAR(50) = 'DELA CRUZ, JUAN PONCE SR. ENRILE'
SELECT
SUBSTRING(@Name, 0, CharIndex(',', @Name)) LastName,
REVERSE(SUBSTRING(REVERSE(RIGHT(@Name,LEN(@Name)-CharIndex(',', @Name))), 0, CharIndex(' ', REVERSE(RIGHT(@Name,LEN(@Name)-CharIndex(',', @Name)))))) MiddleName,
REPLACE(REVERSE(RIGHT(REVERSE(RIGHT(@Name,LEN(@Name)-CharIndex(',', @Name))),LEN(REVERSE(RIGHT(@Name,LEN(@Name)-CharIndex(',', @Name))))-CharIndex(' ', REVERSE(RIGHT(@Name,LEN(@Name)-CharIndex(',', @Name))))+1)),',','') FirstName
字符串操作在 SQL Server 中是一个真正的痛点。 如果您必须使用它们,我建议使用APPLY
来定义中间值:
select v1.lastname, rest,
(case when v1.rest like '%,%'
then left(rest, charindex(',', rest) - 1)
else left(rest, len(rest) - charindex(' ', reverse(rest)))
end) as firstname,
(case when v1.rest like '%,%'
then stuff(rest, 1, charindex(',', rest) + 1, '')
else stuff(rest, 1, len(rest) - charindex(' ', reverse(rest)) + 1, '')
end) as lastname
from t cross apply
(values (left(names, charindex(',', names) - 1), stuff(names, 1, charindex(',', names) + 1, ''))
) v1(lastname, rest);
这是一个 db<>fiddle。
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