Extracting part of name from string

Question

I was trying to extract the lastName, firstName, middleName from Name column which contains whole name format.

here's the sample names which I'm trying to extract:

DELA CRUZ, JUAN PONCE SR. ENRILE
ATIENZA, ROBERTO JR. SANTO
GONZA, MARK ANTHONY, DELLY-LO

I want to extract them like these:

    LastName    | FirstName       | MiddleName
    DELA CRUZ   | JUAN PONCE SR.  | ENRILE
    ATIENZA     | ROBERTO JR.     | SANTOS
    GONZA       | MARK ANTHONY    | DELLY

This is my script so far

DECLARE @Name    VARCHAR(50) = 'DELA CRUZ, JUAN PONCE SR. ENRILE'

SELECT
SUBSTRING(@Name, 0, CharIndex(',', @Name)) LastName,
REVERSE(LEFT(REVERSE(@Name), CharIndex(' ', reverse(@Name))-1)) MiddleName

I also having a problem when extracting middle with -LO suffix.

thank you

Answer 1

Try this below logic (modified your one)

DECLARE @Name    VARCHAR(50) = 'DELA CRUZ, JUAN PONCE SR. ENRILE'

SELECT
SUBSTRING(@Name, 0, CharIndex(',', @Name)) LastName,
REVERSE(SUBSTRING(REVERSE(RIGHT(@Name,LEN(@Name)-CharIndex(',', @Name))), 0, CharIndex(' ', REVERSE(RIGHT(@Name,LEN(@Name)-CharIndex(',', @Name)))))) MiddleName,
REPLACE(REVERSE(RIGHT(REVERSE(RIGHT(@Name,LEN(@Name)-CharIndex(',', @Name))),LEN(REVERSE(RIGHT(@Name,LEN(@Name)-CharIndex(',', @Name))))-CharIndex(' ', REVERSE(RIGHT(@Name,LEN(@Name)-CharIndex(',', @Name))))+1)),',','') FirstName         

Answer 2

String operations are a real pain in SQL Server. I recommend using APPLY to define intermediate values, if you have to use them:

select v1.lastname, rest, 
       (case when v1.rest like '%,%'
             then left(rest, charindex(',', rest) - 1)
             else left(rest, len(rest) - charindex(' ', reverse(rest)))
        end) as firstname,
       (case when v1.rest like '%,%'
             then stuff(rest, 1, charindex(',', rest) + 1, '')
             else stuff(rest, 1, len(rest) - charindex(' ', reverse(rest)) + 1, '')
        end) as lastname
from t cross apply
     (values (left(names, charindex(',', names) - 1), stuff(names, 1, charindex(',', names) + 1, ''))
     ) v1(lastname, rest);

Here is a db<>fiddle.